The net ionic equation for the given reaction is: 2Au3+ + 3Sn → 3Sn2+ + 2Au. In this reaction, gold (III) ions are reduced to form gold solid, while tin solid is oxidized to form tin (II) ions. Only the ions that participate in the reaction are included in the net ionic equation.
Au is the symbol of gold, and it does not react with hydrochloric acid. It is only dissolved in Aqua Regia.
One assumes this is a single displacement reaction. 2Au + FeSO4 --> Au2SO4 + Fe
The Merrill-Crowe process is a method used for the precipitation of gold and silver from cyanide solutions. The chemical equation for the process involves the addition of zinc dust to the solution, which reacts with the gold and silver cyanide complexes, forming a zinc-gold/silver precipitate and releasing cyanide ions back into the solution to be reused.
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
2Au + 4KCN + O2 → 2KAu(CN)2
Au is the symbol of gold, and it does not react with hydrochloric acid. It is only dissolved in Aqua Regia.
2Au+(aq) + Cu(s) → 2Au(s) + Cu2+(aq)That formula is correct. It represents the net ionic equation of a complex oxidation-reduction reaction. Note that mass (2Au, 1Cu) and charge (2+) are preserved on both sides. The copper is oxidized from 0 to 2+, whereas the gold is reduced from 1+ to 0. This makes copper the reducing agent and gold the oxidizing agent.In layman's terms, when you put solid copper into a solution with gold in it, the gold will precipitate out. The reason the reaction happens at all is because gold is so resistant to being oxidized. Essentially any metal, including copper, will force gold out of solution.That equation, as stated above, is a net ionic equation and is the simplified form of a larger equation, such as:Molecular: 2AuNO3(aq) + Cu(s) → Cu(NO3)2(aq) + 2Au(s)Ionic: 2Au+(aq) + 2NO3-(aq) + Cu(s) → Cu2+(aq) + 2NO3-(aq) + 2Au(s)Note that the nitrate ions are the same on both sides and do not participate in the overall reaction, hence their removal to form the net ionic equation.
One assumes this is a single displacement reaction. 2Au + FeSO4 --> Au2SO4 + Fe
The Merrill-Crowe process is a method used for the precipitation of gold and silver from cyanide solutions. The chemical equation for the process involves the addition of zinc dust to the solution, which reacts with the gold and silver cyanide complexes, forming a zinc-gold/silver precipitate and releasing cyanide ions back into the solution to be reused.
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
2Au + 4KCN + O2 → 2KAu(CN)2
I'm not sure if you are asking about: e-ax2 or e-ax^2. Use the carets=^ in the future to raise something to a power.For e-ax2:You need to remember that: (ex)`= exalso: (eax)`= aeax, assuming a is a constant and not a function of x.Justrecognizeany constant drops down to the front.Therefore: (e-ax2)`=-2ae-ax2, treat the negative just as a constant or (-1)For e-ax^2: this one is a little bit trickier:We can just use u-substitution.Let u = x2.u` = 2xIf we substitute the u for x^2, we have: e-au , and we know the deriviate of that is -ae-2au, but we need to multiply by u` as well to get:(-ae-2au)(2x) = -2xae-2au, then we can just plug u back in.u = x2, so:-2xae-2au = -2xae-2ax^2And that is the answer.(e-ax^2)`= -2xae-2ax^2
When solid zinc reacts with aqueous gold(III) nitrate, zinc displaces gold in the compound through a single displacement reaction. The products of the reaction are gold metal and aqueous zinc nitrate.
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
Well what chemically happens is an exchage of electrons. In an ionic bond, a metal (gold in this case) reacts with a non-metal (chlorine) to form an ionic compound. So Gold, or Au, most commonly has a charge of 3+. This means that normally to have a full outer shell of electrons, gold needs to give up three electrons, which is a loss of 3 negatives, which gives it a postivie charge. For chlorine to be 'happy' and have a full outer shell, it needs to gain one electron giving it a charge of 1-. These elements will only give up their electrons in specific situations and one is a bond. When chlorine gets put into an area with gold, then the chlorine takes an electron off of the gold, but since gold still needs to lose more electrons, then for every one gold atom losing electrons there must be 3 chlorine atoms taking them away. When this happens yu get a postively charged ion, Au+3 and three negatively charged ions, Cl-1. Since one of these ions is positive and the other negative, they act the same way as two different poles of a magnet would react. They attract to each other and stick together. Since they are now stuck together we know them as the compound AuCl3 or gold (III) chloride. (the III is a roman numeral for one, representing which type of gold was reacting) And that's whats happening when you put some solid gold into a chamber full of chlorine gas!Here is the chemical formula just in case you want to see it:2Au(s) + 3Cl2(g) --> 2AuCl3(s) Also if you are wondering, chlorine comes in pairs in its naturally occurring state, so we have to increase the number of gold around in order to properly react.
Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-
The majority of asteroids (majority meaning "more than half") of the asteroids are in a poorly-defined area known as the asteroid belt between the orbits of Mars and Jupiter. That's about - and I really do mean "ABOUT" - 2AU to 4AU from the Sun. If over half of the asteroids are in the asteroid belt, that still leaves a large number of asteroids that are NOT in the asteroid belt, and in fact, asteroids are found almost anywhere in the solar system. And in fact, the month doesn't go by that we don't discover new asteroids just passing VERY close to the Earth. There was one last week (as I write this in July, 2012) that passed within 20,000 miles of the Earth; as close as the geosynchronous orbit satellites!