The net ionic equation for BaCl2 + ZnSO4 is Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s). Since Zn^2+ and Cl^- ions do not form a precipitate, they are considered as spectator ions and are not included in the net ionic equation.
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The net ionic equation for the reaction is: Ba^2+(aq) + AsO4^3-(aq) → BaAsO4(s). This equation shows the formation of solid barium arsenate from the aqueous ions of barium and arsenate present in the reactants.
The net ionic equation for the reaction between zinc and copper(II) sulfate is: Zn(s) + Cu2+ (aq) -> Zn2+ (aq) + Cu(s). This equation shows the transfer of electrons between zinc and copper ions, resulting in zinc ions in solution and solid copper being formed.
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
The ionic equation for the reaction between silver nitrate (AgNO3) and barium chloride (BaCl2) is: Ag+(aq) + Cl-(aq) → AgCl(s) This equation shows the formation of a white precipitate of silver chloride.
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The net ionic equation for the reaction is: Ba^2+(aq) + AsO4^3-(aq) → BaAsO4(s). This equation shows the formation of solid barium arsenate from the aqueous ions of barium and arsenate present in the reactants.
The net ionic equation for the reaction between zinc and copper(II) sulfate is: Zn(s) + Cu2+ (aq) -> Zn2+ (aq) + Cu(s). This equation shows the transfer of electrons between zinc and copper ions, resulting in zinc ions in solution and solid copper being formed.
The net ionic equation for sodium sulfate (Na2SO4) and barium chloride (BaCl2) when a precipitate of barium sulfate (BaSO4) is formed is: Ba^2+ + SO4^2- → BaSO4 The spectator ions (Na^+ and Cl^-) are not included in the net ionic equation because they do not participate in forming the precipitate.
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.
the spectator ions are removed
The net ionic equation for the reaction between barium chloride (BaCl2) and ammonium sulfate (NH4)2SO4 is Ba2+(aq) + SO4 2-(aq) -> BaSO4(s), where a white precipitate of barium sulfate is formed. The spectator ions, which are not involved in the reaction, are Cl- and NH4+.
The net ionic equation for the reaction between potassium sulfate (K2SO4) and barium chloride (BaCl2) is: 2K+ (aq) + SO4^2- (aq) + Ba^2+ (aq) + 2Cl- (aq) → 2K+ (aq) + 2Cl- (aq) + BaSO4 (s). In this equation, the spectator ions (K+ and Cl-) are removed to show only the species that are involved in the chemical change.