0
2C4H10 + 13O2 ---------> 8CO2 + 10H2O
This is a combustion reaction because carbon dioxide and water are products. This equation is balanced because on both sides there are 8 carbon atoms, 20 hydrogen atoms, and 26 oxygen atoms. Also these are the lowest possible coefficients (because there cannot be fractional coefficients).
The trick to balancing this equation is to realize that the oxygen reactant is diatomic (so it starts out as O2).
What else can I help you with?
How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?
For the combustion of butane C4H10, the balanced chemical equation is: 2C4H10 + 13O2 -> 8CO2 + 10H2O. First, calculate the moles of butane: 58.0 g / 58.12 g/mol = 1 mole. From the balanced equation, 2 moles of butane produce 8 moles of CO2, so 1 mole of butane will produce 4 moles of CO2.
How many moles of oxygen are required to react with 5 moles of butane?
Assuming complete combustion of butane, you need 15 moles of oxygen to react with 5 moles of butane according to the balanced chemical equation: [ 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O ]
Is the following equation balanced 2SO2 o2 2SO3?
No, the chemical equation is not balanced. The correct balanced equation is 2SO2 + O2 → 2SO3.
If 5.50 mol of butane are reacted how many moles of water vapor are produced?
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
What happens when 1mole O2 react with butane?
When 1 mole of O2 reacts with butane (C4H10), a combustion reaction occurs forming carbon dioxide (CO2) and water (H2O) as products. The balanced chemical equation for the reaction is 2C4H10 + 13O2 -> 8CO2 + 10H2O.
What is the equation for butane oxygen?
The balanced chemical equation for the combustion of butane (C₄H₁₀) in oxygen (O₂) is: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?
For the combustion of butane C4H10, the balanced chemical equation is: 2C4H10 + 13O2 -> 8CO2 + 10H2O. First, calculate the moles of butane: 58.0 g / 58.12 g/mol = 1 mole. From the balanced equation, 2 moles of butane produce 8 moles of CO2, so 1 mole of butane will produce 4 moles of CO2.
How many moles CO2 form when 58 g of butane C4H10 burn in oxygen?
To determine the moles of CO2 formed when 58 g of butane burns in oxygen, first, calculate the moles of butane using its molar mass. Then, use the stoichiometry of the balanced chemical equation to find the moles of CO2 formed, as per the ratio of the coefficients in the balanced equation.
How many grams of oxygen are needed for the complete combustion of the butane in the lighter?
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
What is the balanced equation for the complete combustion of CH3-CH2-CH2-CH3 C4H10?
The balanced equation for the complete combustion of C4H10 is 2C4H10 + 13O2 → 8CO2 + 10H2O. This equation shows that butane (C4H10) reacts with oxygen to produce carbon dioxide and water.
How many moles of oxygen are required to react with 5 moles of butane?
Assuming complete combustion of butane, you need 15 moles of oxygen to react with 5 moles of butane according to the balanced chemical equation: [ 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O ]
What is the formula equation for Butane?
The formula is 2 x C2H5 = C4H10. :)
How many grams of Oxygen are needed to completely react with 5.0 grams of butane in a butane lighter?
To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.
What is the balanced equation for C4H10 plus O2?
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
What is the mass of water produced when 7.01 g of butane reacts in an excess of oxygen?
The equation is 2C4H10 + 13O2 --> 8CO2 + 10H2O This means that for each mole of butane there are 5 moles of water produced. We have 7.01 g of butane = 7.01/58 moles of butane = 0.12 moles. Thus we will get 5 x 0.12 moles of water, = 5 x 0.12 x 18 g of water = 10.88 g.
Is the following equation balanced 2SO2 o2 2SO3?
No, the chemical equation is not balanced. The correct balanced equation is 2SO2 + O2 → 2SO3.
c4h10 o2 co2 h2o balance?
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
