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We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
To determine the number of moles of oxygen needed to react with 4.52 moles of carbon monoxide (CO), we refer to the balanced chemical equation for the reaction: 2 CO + O₂ → 2 CO₂. From the equation, 2 moles of CO react with 1 mole of O₂. Therefore, to find the moles of O₂ required, we can use the ratio: (4.52 moles CO) × (1 mole O₂ / 2 moles CO) = 2.26 moles of O₂. Thus, 2.26 moles of oxygen are needed to react with 4.52 moles of CO.
The nunber of moles of oxygen is 2,5.
The answer is 3,375 moles oxygen.
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
To determine the number of moles of oxygen needed to react with 4.52 moles of carbon monoxide (CO), we refer to the balanced chemical equation for the reaction: 2 CO + O₂ → 2 CO₂. From the equation, 2 moles of CO react with 1 mole of O₂. Therefore, to find the moles of O₂ required, we can use the ratio: (4.52 moles CO) × (1 mole O₂ / 2 moles CO) = 2.26 moles of O₂. Thus, 2.26 moles of oxygen are needed to react with 4.52 moles of CO.
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
The nunber of moles of oxygen is 2,5.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
The answer is 3,375 moles oxygen.
1,8 moles of oxygen are necessary.
When 1 mole of O2 reacts with butane (C4H10), a combustion reaction occurs forming carbon dioxide (CO2) and water (H2O) as products. The balanced chemical equation for the reaction is 2C4H10 + 13O2 -> 8CO2 + 10H2O.
To determine how many moles of oxygen are needed to completely react with isooctane (C₈H₁₈), we can use the balanced combustion reaction: 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O. From this equation, 2 moles of isooctane react with 25 moles of oxygen, indicating that 1 mole of isooctane requires 12.5 moles of oxygen. Therefore, for 4 moles of isooctane, 4 × 12.5 = 50 moles of oxygen are needed.