Ba+2 C2H3O2-1 <---- these are the ions and their charges
Ba+2 C2H3O2-1 C2H3O2-1 <--- the charges have to add up to zero, so one +2 barium ion cancels out two -1 acetate ions
Ba(C2H3O2)2<--- simplify
These are the ions and their charges: Ba+2 C2H3O2-1
The charges have to add up to zero, so one +2 barium ion cancels out two -1 acetate ions. The ratio of barium to acetate would then be 1:2, with a formula of Ba(C2H3O2)2
2HCl+ Ba(CH3COO)2 2CH3COOH+ BaCl2
barium acetate- Ba(C2H3O2)2 * H2O
i believe it is
Ba(C2H3O2)2
Formula: (CH3COO)2Ba
Formula: (CH3COO)2Ba
Ba(CH3COO)2
BaC2H3O2
Ag+ + I- --> AgI
The equation is:Ba+ + (SO4)2- = BaSO4(s)
SO42- + Ba2+ --> BaSO4
Cu(CH3COO)2 + Na2CO3 = CuCO3 + 2 CH3COONa
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.
All elements are disassociated so there is no net Ionic equation
Ionic
lead II acetate and barium chloride equation
Ag+ + I- --> AgI
It all dissolves.
penis
sss
The equation is:Ba+ + (SO4)2- = BaSO4(s)
SO42- + Ba2+ --> BaSO4
sodium acetate = Na+C2H3O2- (a salt) nitric acid = HNO3 equation: NaC2H3O2 + HNO3 --> NaNO3 + C2H4O2
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
BaCl2 + CuSO4 = BaSO4 = CuCl2