The equation for the beta decay of 3H is:
13H --> 23He + -10e
where -10e represents a negative beta particle or electron.
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
Hydrogen-3, also known as tritium, is a rare and radioactive isotope of hydrogen that is not commonly found in nature. It is primarily produced artificially in nuclear reactors and particle accelerators.
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
The fusion of deuterium (D) and hydrogen (H) involves the fusion of two deuterium nuclei to form a helium-3 nucleus and a neutron. The equation for this reaction is: 2D + 1H → 3He + n + energy.
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
Alpha, Beta, and Gamma
Helium-3 is not produced; it is a naturally occurring isotope formed through the decay of tritium. It can also be extracted during the operation of nuclear reactors and obtained through the decay of tritium in nuclear weapons.
When a hydrogen-3 nucleus undergoes radioactive decay, it emits a beta particle (specifically an electron) and an anti-neutrino to transform into helium-3.
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
The word equation for ammonia is 3 H2 + N2 → 2 NH3 (this is a balance equation) The formula (atom) is NH3 for ammonia
The lightest "element" that can undergo radioactive decay is the isotope hydrogen-3, which undergoes beta decay. The lightest element with no radioactively stable isotopes is technetium, and its isotopes have different modes of decay.
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
Hydrogen-3, also known as tritium, is a rare and radioactive isotope of hydrogen that is not commonly found in nature. It is primarily produced artificially in nuclear reactors and particle accelerators.
The equation for the beta decay of 87Kr is: 3687Kr --> 3787Rb + -10e where -10e represents a negative beta particle or electron.
if you bombard a lithium 6 atom with a neutron, then it will form a helium 4 or alpha decay particle and a hydrogen 3 atom, but i dont see that happening, i would think you would need a bigger atom for it to go through radioactive decay, but im just giving my opinion, it could happen just as surely as i think it doesnt. but if alpha decay was to happen to a lithium 6 atom from neutron bombardment, you would get a helium 4 atom and a hydrogen 3 atom.
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.