Here's your equation for the beta minus decay of carbon-14: 614C => 714N + e- + ve An atom of carbon-14 transforms into an atom of nitrogen-14 here. In carbon-14, a down quark in a neurton becomes an up quark. This change, mediated by the weak interaction or weak force, changes that neutron into a proton. This creates another element, the nitrogen, and an electron is created within the nucleus and then is ejected along with an antineutrion. Use the link below to learn more about beta decay.
Lead-209 undergoes beta- decay to become Bismuth-209 82209Pb --> 83209Bi + -10e + v-e emitting an electron and an electron antineutrino.
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
The nuclear equation for the beta decay of Sn-126 is: Sn-126 -> Sb-126 + e- + anti-neutrino
The equation for the beta decay of 3H is: 13H --> 23He + -10e where -10e represents a negative beta particle or electron.
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
Americium-244 undergoes beta decay: 95244Am --> 96244Cm + -10e where -10e is a negative beta particle or electron.
All nuclear decay is spontaneous.
Lead-209 undergoes beta- decay to become Bismuth-209 82209Pb --> 83209Bi + -10e + v-e emitting an electron and an electron antineutrino.
The nuclear decay equation for Po-208 is: Po-208 → Pb-204 + He-4
Beta Particle
Natural chromium is stable and does not decay/
Energy and electrical charge are two quantities that are always conserved in nuclear decay equation.
The equation for the beta decay of 137Cs:55137Cs --> 56137Ba + -10e where the e is a negative beta particle or electron.
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
The decay equation is:Co-60----------------------Ni-60 + e-
Carbon-14 undergoes beta decay, becoming nitrogen-14 which is stable.