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How many moles of hydrogen sulfide are contained in a 64.6-g sample of this gas?
To find the number of moles of hydrogen sulfide, divide the given mass by the molar mass of hydrogen sulfide. The molar mass of hydrogen sulfide is approximately 34.08 g/mol. Thus, 64.6 g / 34.08 g/mol = 1.9 moles of hydrogen sulfide in the sample.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O2?
First, calculate the number of moles of each gas: 7.0 g H2S = 0.25 moles, 10.0 g CH4 = 0.28 moles, and 12.0 g O2 = 0.38 moles. Next, calculate the total moles of gas in the mixture: 0.25 + 0.28 + 0.38 = 0.91 moles. Finally, calculate the mole fraction of H2S: 0.25 moles H2S / 0.91 moles total = 0.275 or 27.5%.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S?
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.
Mass And No Of Molecules In 18000 cm3 Of H2S gas at S.T.P?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 L or 22,400 cm3. Therefore, 18,000 cm3 of H2S gas at STP corresponds to 18,000/22,400 = 0.8 moles. Each mole of a gas contains 6.022 x 10^23 molecules, so 0.8 moles of H2S gas would contain 0.8 x 6.022 x 10^23 = 4.82 x 10^23 molecules.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O?
First calculate the moles of each gas using their molar masses (H2S = 34 g/mol, CH4 = 16 g/mol, O2 = 32 g/mol). Then find the total moles in the mixture. Lastly, divide the moles of H2S by the total moles to get the mole fraction of H2S in the mixture.
How many moles of hydrogen sulfide are contained in a 64.6-g sample of this gas?
To find the number of moles of hydrogen sulfide, divide the given mass by the molar mass of hydrogen sulfide. The molar mass of hydrogen sulfide is approximately 34.08 g/mol. Thus, 64.6 g / 34.08 g/mol = 1.9 moles of hydrogen sulfide in the sample.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O2?
First, calculate the number of moles of each gas: 7.0 g H2S = 0.25 moles, 10.0 g CH4 = 0.28 moles, and 12.0 g O2 = 0.38 moles. Next, calculate the total moles of gas in the mixture: 0.25 + 0.28 + 0.38 = 0.91 moles. Finally, calculate the mole fraction of H2S: 0.25 moles H2S / 0.91 moles total = 0.275 or 27.5%.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S?
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.
How many molecules are in 7.4 g H'S?
By definition, Avogadro's Number is the number of molecules or formula units in the number of grams corresponding to the gram molecular weight or gram formula unit, and by experiment, Avogadro's Number is about 6.022 X 1023. Therefore, 7.75 X 1025 formula units contains (7.75 X 1025/6.022 X 1023) or 1.29 X 102 moles or formula units, to the justified number of significant digits.
Mass And No Of Molecules In 18000 cm3 Of H2S gas at S.T.P?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 L or 22,400 cm3. Therefore, 18,000 cm3 of H2S gas at STP corresponds to 18,000/22,400 = 0.8 moles. Each mole of a gas contains 6.022 x 10^23 molecules, so 0.8 moles of H2S gas would contain 0.8 x 6.022 x 10^23 = 4.82 x 10^23 molecules.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O?
First calculate the moles of each gas using their molar masses (H2S = 34 g/mol, CH4 = 16 g/mol, O2 = 32 g/mol). Then find the total moles in the mixture. Lastly, divide the moles of H2S by the total moles to get the mole fraction of H2S in the mixture.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S 2H2S plus 3O2 2SO2 plus 2H2O?
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.
How may moles of hydrogen are in H2S?
There are no moles.There are 2 atoms in one molecule.
When hydrochloric acid reacts with sodium sulfide hydrogen sulfide gas and sodium chloride are produced. How many moles of H2S will be generated by 2.56 moles of HCl?
The balanced chemical reaction between hydrochloric acid (HCl) and sodium sulfide (Na2S) can be represented as: [ 2 \text{HCl} + \text{Na}_2\text{S} \rightarrow \text{H}_2\text{S} + 2 \text{NaCl} ] From the equation, 2 moles of HCl produce 1 mole of H2S. Therefore, if you start with 2.56 moles of HCl, it will generate: [ \frac{2.56 , \text{moles HCl}}{2} = 1.28 , \text{moles of H2S} ] Thus, 2.56 moles of HCl will produce 1.28 moles of H2S.
What volumes of h2s gas and oxygen are necessary to produce 14.2 l of sulfur dioxide gas the balanced equation is 2 h2s 3 o2 2 so2 2 H2O?
Using the balanced chemical equation, you can see that 2 moles of H2S will produce 2 moles of SO2. Therefore, 1 mole of H2S will produce 1 mole of SO2. Given that 14.2 L of SO2 gas is produced, you would need the same volume of H2S gas. For oxygen, the ratio of H2S to O2 is 3:2, so 1.5 times the volume of H2S gas is needed in O2 gas.
What is the oxidation number of sulphur in the equation of combustion of H2S?
The oxidation number of sulphur in H2S is 2.
How many grams of oxygen are needed to react with 2.5 grams of dihydrogen sulfide?
Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
