607 x 1 mol / 83.8 = 7.24 mol
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.
7.24 moles.
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
To determine the number of moles in 1.23 grams of krypton, first find the molar mass of krypton (Kr), which is approximately 83.80 g/mol. Then, divide the given mass (1.23 g) by the molar mass of krypton to find the number of moles. In this case, 1.23 g / 83.80 g/mol ≈ 0.015 moles of krypton.
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
It seems like there might be a mistake in your question. Krypton is a gas and its atomic mass is around 83.80 g/mol, not 30.00 g/mol. So, if you have 30.00 g of krypton, you would have approximately 0.358 moles of krypton.
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
4.56 moles Kr x 83.798 g/mole = 382.119 grams = 382 grams (to 3 significant figures)NOTE: You should not use more than 3 significant figures since 4.56 moles limits the precision. Thus the answers of 381.66g and 382.1188 g are incorrect.
The number of moles is mass in g/molar mass in g.
The formula is: number of moles = g Be/9,012.
The number of moles 9,92.10e-5.
0.0027 moles.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.