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Al(NO3)3 contains 9 oxy atoms per formula unit.

4.88x10-3 mol x (6.022x1023form units / mole) x (9 atoms oxy / Form Unit)

= multiply and get the answer

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11y ago
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Ismael

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7mo ago

im getting 2.938 x 10^19

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Q: What is the number of oxygen atoms in 4.88x10-3 mol of AlNO33?
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