it will kill everybody and you will die
2Mg(s) + O2(g) ==> 2MgOMg ===> Mg^2+ + 2e- [x2 to balance electrons] = oxidation half reactionO2 + 4e- ===> 2O^2-So, the final oxidation half reaction will be:2Mg(s) ===> 2Mg^2+ + 4e-
Mg equals Mg2+ plus 2e-
Mg equals Mg2+ plus 2e-
In the reaction between magnesium and oxygen (2Mg + O₂ → 2MgO), magnesium loses electrons (oxidizes) to form Mg²⁺ ions, while oxygen gains electrons (reduces) to form O²⁻ ions in magnesium oxide (MgO). The transfer of electrons between the magnesium and oxygen atoms demonstrates a redox process, where oxidation and reduction occur simultaneously.
2Mg + O2 --------> 2MgO
The oxidation half-reaction for the conversion of 2Mg to MgO is: 2Mg(s) -> 2Mg^2+(aq) + 4e^-
2Mg(s) + O2(g) ==> 2MgOMg ===> Mg^2+ + 2e- [x2 to balance electrons] = oxidation half reactionO2 + 4e- ===> 2O^2-So, the final oxidation half reaction will be:2Mg(s) ===> 2Mg^2+ + 4e-
Mg equals Mg2+ plus 2e-
Mg equals Mg2+ plus 2e-
How many electrons are taken up by an oxidant in the 1st halfreaction (oxidant reaction),and how many electrons are given free by a reductant in the 2st halfreaction (reductant reaction)
Mg equals Mg2+ plus 2e-
How many electrons are taken up by an oxidant in the 1st halfreaction (oxidant reaction),and how many electrons are given free by a reductant in the 2st halfreaction (reductant reaction)
-1.68 V
An example of an oxidation reaction is the reaction between magnesium and oxygen to form magnesium oxide: 2Mg + O2 -> 2MgO. In this reaction, magnesium loses electrons to form magnesium ions, Mg²⁺, thereby undergoing oxidation.
Hmmmm is that a trick question? Answer: 2mg
hydromorphone 2mg
In the reaction between magnesium and oxygen (2Mg + O₂ → 2MgO), magnesium loses electrons (oxidizes) to form Mg²⁺ ions, while oxygen gains electrons (reduces) to form O²⁻ ions in magnesium oxide (MgO). The transfer of electrons between the magnesium and oxygen atoms demonstrates a redox process, where oxidation and reduction occur simultaneously.