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2Mg(s) + O2(g) ==> 2MgOMg ===> Mg^2+ + 2e- [x2 to balance electrons] = oxidation half reaction

O2 + 4e- ===> 2O^2-

So, the final oxidation half reaction will be:

2Mg(s) ===> 2Mg^2+ + 4e-


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6y ago
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Anonymous

Lvl 1
3y ago

Mg --> Mg2+ + 2e-

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Q: What is the oxidation half-reaction for 2Mg plus O22MgO?
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