+6
In CrO3, the oxidation number of chromium (Cr) is +6 and the oxidation number of oxygen (O) is -2. This is because oxygen typically has an oxidation number of -2, and there are three oxygen atoms in CrO3 to give a total charge of -6. To balance the charge, the chromium atom must have an oxidation number of +6.
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
+2 for Ca, +6 for Cr, -2 for each O
The oxidation number for Cr in Cr2O7^2- is +6.
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
In CrO3, the oxidation number of chromium (Cr) is +6 and the oxidation number of oxygen (O) is -2. This is because oxygen typically has an oxidation number of -2, and there are three oxygen atoms in CrO3 to give a total charge of -6. To balance the charge, the chromium atom must have an oxidation number of +6.
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
+2 for Ca, +6 for Cr, -2 for each O
The oxidation number for Cr in Cr2O7^2- is +6.
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
+3 for Cr and -2 for O
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
The oxidation number of Cr in MgCrO4 is +6. This is because oxygen is typically assigned an oxidation number of -2, and the overall charge of the compound is 0, so the oxidation number of magnesium (+2) and oxygen (-2) must be balanced by the oxidation number of Cr (+6).
The oxidation number of chromium (Cr) in CrO4^2- is +6. Since each oxygen atom has an oxidation number of -2, and the overall charge of the polyatomic ion is -2, the oxidation number of chromium can be determined by solving the equation: (oxidation number of Cr) + 4(-2) = -2.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number for Cr in CrPO4 is +3. This is because the overall charge of the compound is neutral, and the oxidation numbers for oxygen (-2) and phosphorus (+5) are known. By calculation, we determine the oxidation number of Cr to be +3.