-2 for oxygen and +6 for chromium
The oxidation number for Cr in CrO3 is +6. Each oxygen atom has an oxidation number of -2, and since there are three oxygen atoms in CrO3, the total oxidation number contributed by oxygen is -6. This means that the oxidation number of chromium must be +6 to balance the overall charge of the compound, which is neutral.
The oxidation number of each carbon atom in C6H8O6 is +4. Each hydrogen atom has an oxidation number of +1, and each oxygen atom has an oxidation number of -2.
The oxidation number for hydrogen in a neutral atom is 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
In S2Cl2, each sulfur atom has an oxidation number of 0, and each chlorine atom has an oxidation number of -1.
The oxidation number for Cr in CrO3 is +6. Each oxygen atom has an oxidation number of -2, and since there are three oxygen atoms in CrO3, the total oxidation number contributed by oxygen is -6. This means that the oxidation number of chromium must be +6 to balance the overall charge of the compound, which is neutral.
The oxidation number of each carbon atom in C6H8O6 is +4. Each hydrogen atom has an oxidation number of +1, and each oxygen atom has an oxidation number of -2.
The oxidation number for hydrogen in a neutral atom is 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
Oxidation is a chemial reaction; the atom and the number of neutrons remains unchanged.
In S2Cl2, each sulfur atom has an oxidation number of 0, and each chlorine atom has an oxidation number of -1.
The oxidation number of an atom describes the number of electrons that an element has partially/entirely accepted/donated. A neutral atom has oxidation number of 0. When forming an ion, the overall oxidation number is equivalent to its charge.
The central carbon atom has an oxidation number of -2 (O is -2, H is +1)
Each Br atom has an oxidation number of zero.
The oxidation number of sulfur in H2S2O8 is +6. Each oxygen atom has an oxidation number of -2, and each hydrogen atom has an oxidation number of +1. By setting up an equation and solving for sulfur's oxidation number, you will find it to be +6.
Oxidation is the process in which an atom loses electrons, resulting in an increase in its oxidation number. This occurs when an element undergoes chemical reactions where it loses electrons to become more positively charged. The oxidation number reflects the number of electrons that an atom has gained or lost in a compound.
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6