This question is not complete, kindly provide all the information to enable me correctly answer this.
the answer is 94,97136
how many atoms are present in PO ion
its -3
3
3-
germanium has an oxidation number of +4, phosphate is PO4 has an oxidation number -3. Ge3(PO4)4
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
This compound is insoluble in water. Calcium generally shows +2 oxidation number.
It is 5.
Based on the formula of M3(PO4)4, that would mean the M has an oxidation number of 4+, so the metal chloride would take the form of MCl4
germanium has an oxidation number of +4, phosphate is PO4 has an oxidation number -3. Ge3(PO4)4
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
This compound is insoluble in water. Calcium generally shows +2 oxidation number.
It is 5.
Based on the formula of M3(PO4)4, that would mean the M has an oxidation number of 4+, so the metal chloride would take the form of MCl4
Sodium Phosphate why because you first would separate Na or sodium being a metal and the charge of it being +1 or the oxidation number then PO4 is a compound being Phosphate charge -3 then all you would do is criss cross them to find name of compound simply it be Sodium and Phosphate
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
Oxidation number of Si is +4.Oxidation number of O is -2.