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germanium has an oxidation number of +4, phosphate is PO4 has an oxidation number -3. Ge3(PO4)4
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.
It is 5.
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.
germanium has an oxidation number of +4, phosphate is PO4 has an oxidation number -3. Ge3(PO4)4
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.
It is 5.
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.
The oxidation number of what in K3PO4? In that compound the oxidation number of oxygen is -2, the oxidation number of potassium is +1, and the oxidation number of phosphorus is +5.Realistically, in most compounds you can generally take it as a given that the oxidation number of oxygen is -2 and the oxidation number of any alkali metal is +1. In potassium phosphate, that only leaves the oxidation number of phosphorus to figure out, and since they have to come out to a total of zero ...The oxidation number of a compound is essentially a meaningless phrase.
The sum of the oxidation numbers in the phosphate ion (PO4^3-) is -3. Each oxygen atom has an oxidation number of -2, totaling -8. The oxidation number for phosphorus is +5 to offset the oxygen atoms and give a total charge of -3 for the ion.
To find the oxidation number of phosphorus in phosphate (PO4), consider that oxygen typically has an oxidation number of -2. Since there are four oxygen atoms in phosphate, their total charge is -8. The overall charge of the phosphate ion is -3, so the oxidation number of phosphorus can be calculated as +5 to balance the charges.
+5 The phosphate anion is PO4^(3-) . Using oxygen as the yardstick (standard ) at '-2' The the four oxygens have an overall oxidation of 4 x -2 = -8 Then creating a sum P - 8 = -3 ( The anionic chagre0. P = -3 + 8 P = +5 . NB In the nitrogen group , which includes phosphorus, the elements have variable oxidation states.
The cobalt in the formula given has an oxidation number of +3, so that the total charge of the two cobalt ions will balance the total charge of the 3 oxide ions, which have an oxidation number of -2 each.
The oxidation number of Au (gold) in AuPO4 is +3. This is because in most compounds, the oxidation number of oxygen is -2, and the overall charge of PO4 3- ion is -3. So, the oxidation number of Au must be +3 to balance the charges.
The formula for manganese (II) phosphide is Mn3P2. This compound is formed by the combination of manganese with a +2 oxidation state and phosphorus.