It is 5.
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
The oxidation state of phosphorus (P) in PO4 3- is +5. This is because oxygen typically has an oxidation state of -2, and since there are four oxygen atoms in PO4 3-, the overall charge of -3 forces the phosphorus to have an oxidation state of +5 in order to balance out the charges.
It is 5.
+5 The phosphate anion is PO4^(3-) . Using oxygen as the yardstick (standard ) at '-2' The the four oxygens have an overall oxidation of 4 x -2 = -8 Then creating a sum P - 8 = -3 ( The anionic chagre0. P = -3 + 8 P = +5 . NB In the nitrogen group , which includes phosphorus, the elements have variable oxidation states.
The oxidation state of phosphorus (P) in the compound Ca3(PO4)2 is +5. This is because the overall charge of the phosphate ion (PO4)^3- is -3, and since there are 2 phosphate ions in the compound, the total charge contributed by phosphorus is -6. Since there are 7 oxygen atoms with an oxidation state of -2 each, the oxidation state of phosphorus is calculated to be +5 to balance the charge.
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
The oxidation state of phosphorus (P) in PO4 3- is +5. This is because oxygen typically has an oxidation state of -2, and since there are four oxygen atoms in PO4 3-, the overall charge of -3 forces the phosphorus to have an oxidation state of +5 in order to balance out the charges.
It is 5.
The charge of a phosphorus (P) ion can vary depending on its oxidation state. For example, in the common phosphate ion (PO4)3-, phosphorus has a charge of +5.
+5 The phosphate anion is PO4^(3-) . Using oxygen as the yardstick (standard ) at '-2' The the four oxygens have an overall oxidation of 4 x -2 = -8 Then creating a sum P - 8 = -3 ( The anionic chagre0. P = -3 + 8 P = +5 . NB In the nitrogen group , which includes phosphorus, the elements have variable oxidation states.
The oxidation state of phosphorus (P) in the compound Ca3(PO4)2 is +5. This is because the overall charge of the phosphate ion (PO4)^3- is -3, and since there are 2 phosphate ions in the compound, the total charge contributed by phosphorus is -6. Since there are 7 oxygen atoms with an oxidation state of -2 each, the oxidation state of phosphorus is calculated to be +5 to balance the charge.
germanium has an oxidation number of +4, phosphate is PO4 has an oxidation number -3. Ge3(PO4)4
The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.
+5; each oxygen is -2 giving -8 reduced by the ionic charge of -3 to +5
The oxidation state of phosphate (PO4) is -3. This is because oxygen (O) typically has an oxidation state of -2, so there are 4 oxygen atoms in the phosphate molecule, contributing to a total charge of -8. This leaves the phosphorus atom with an oxidation state of +5 to balance the overall charge to -3.
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.
In H3PO3 each H is 1+ for a total of 3+. Each O is 2- for a total of 6-. So, there is 3+ and 6- giving a net of 3-. In order to make the molecule neutral, P must have an oxidation state of 3+.