-1 for each iodine, +4 for C
In CI4, the oxidation number of chlorine is -1. Since there are 4 chlorine atoms, the total oxidation number contributed by chlorine is -1 x 4 = -4. To neutralize the charge, the oxidation number for the central atom must be +4.
Assuming you mean Cl, with a lowercase L, which is chlorine: As with all elements chlorine has an oxidation number of 0 in it's elemental form. In most of it's compounds its oxidation state is -1, but it can also exist in all oxidation states from -1 to +7 except for +2 and +6.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
In CI4, the oxidation number of chlorine is -1. Since there are 4 chlorine atoms, the total oxidation number contributed by chlorine is -1 x 4 = -4. To neutralize the charge, the oxidation number for the central atom must be +4.
-1 for each iodine, +4 for C
CI4, or carbon tetraiodide, contains one carbon atom and four iodine atoms. Carbon has 4 valence electrons, while each iodine atom has 7 valence electrons. Therefore, the total number of valence electrons in CI4 is 4 (from carbon) + 4 × 7 (from iodine) = 4 + 28 = 32 valence electrons.
Assuming you mean Cl, with a lowercase L, which is chlorine: As with all elements chlorine has an oxidation number of 0 in it's elemental form. In most of it's compounds its oxidation state is -1, but it can also exist in all oxidation states from -1 to +7 except for +2 and +6.
For HClO oxidation No. is '0' . It is a neutrally charged molecule. However, The chlorine atom is in oxidation state (+1). How so???? you may ask . Using oxygen as that standard at '-2' , and hydrogen at '+1' We create a little sum +1 + Cl -2 = 0 ( overall charge on the molecule). Collecting terms Cl - 1 = 0 Cl = + 1 as required. NB When dissolved in water chlorine disproportionates. That is it simultaneously oxidises and reduces., Cl2(aq) = Cl^(+)(aq) + Cl^(-)(aq) It reacts with water molecules to form ;- Cl2 + H2O = HClO + HCl The supply of drinking water from public sources has chlorine bubbled through to act as a bacteriocide (kill the bugs). So tap/faucet water is a very weak solution of hydrochloric acid(HCl) and Hydrogen chlorate(bleach)(HClO). It won't harm you, because the solution is so weak, but just enough to kill the bugs.
CI4
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
Oxidation number of Nb is +4. Oxidation number of O is -2.
The formula for carbon tetraiodide is CI4, which consists of one carbon atom bonded to four iodine atoms.