The rule for hydrogen is that it normally has an oxidation state of +1, EXCEPT in metal hydrides, when it has an oxidation state of -1.
Li is a metal, LiH is a metal hydride.
Does that tell you what you need to know?
The oxidation number of Li in Li2 is +1. The oxidation number of O in Li2O is -2.
The oxidation number of Li in Li2 is +1. Each Li atom has an oxidation number of +1 in ionic compounds.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
Every element on the Periodic Table has an OXIDATION NUMBER of zero, including Lithium.
0 in elemental form +1 in its compounds
The oxidation number of Li in Li2 is +1. The oxidation number of O in Li2O is -2.
The oxidation number of Li in Li2 is +1. Each Li atom has an oxidation number of +1 in ionic compounds.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
Every element on the Periodic Table has an OXIDATION NUMBER of zero, including Lithium.
0 in elemental form +1 in its compounds
The oxidation number of Li in LiNO2 is +1, as it typically has an oxidation number of +1 in its compounds.
This contains H- ion. Li shows +1 oxidation number.
In LiH, the oxidation number of Li is +1 and the oxidation number of H is -1. This is because lithium typically has a +1 oxidation state and hydrogen typically has a -1 oxidation state in ionic compounds.
The oxidation number for Li, or Lithium, is Li+1. Lithium is in the first family on the Periodic Table. Since the element wants to become stable, and it only it needs 8 valence electrons. So therefore, it has to lose an electron. Losing an electron will make it a positive oxidation number.
Atomic lithium has no charge whereas its ion has a +1 charge.
Wjat is 'li3po3'. ??? If you mean Li3PO3, then note the use of Capital and small case letters. For lithium phosphite (Li3PO3) , use oxygen as the standard at '-2' Since there are three oxygens, then the overall oxidation is '-6' The phosphite anion 'PO3^(3-) has an overall charge of '-3', there being three positives from the lithium (3 x Li^(+)). So doing a 'little sum' P + (3 x -2) = -3 ( The anionic charge). P + -6 = -3 Add ''6' to both sides. Hence P = + 3 (The oxidation state of phosphorus. NB Phosphorus is in the same Group(V) as nitrgoen, and like nitrogen , it can exhibit variable oxidation states. Compare with Li3PO4 ( lithium phosphate) . In this compound phosphorus in is oxidation state ' +5 '. Also Note the suffix in the name '+3' is '---ite' , and '+5' is '---ate'.
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.