+1 for each K, +4 for Pt, -1 for each Cl
The oxidation number of Pt (platinum) can vary depending on the compound it is in. In its elemental state, platinum has an oxidation number of 0. In some compounds, such as PtCl4, platinum has an oxidation number of +4.
The oxidation number of Pt in PtCl6 is +4. Each Cl has an oxidation number of -1, and since the overall charge of the complex ion is 0, the oxidation number of Pt must be +4 to balance the charges.
The oxidation number for Pt in PtO is +2. Oxygen typically has an oxidation number of -2, so the sum of the oxidation numbers in PtO must be zero since it is a neutral compound.
The oxidation number of Pt in PtCl4^2- is +2. This is because the overall charge of the complex ion is 2-, and each chlorine atom has an oxidation state of -1, so the oxidation state of Pt must be +2 to balance the charge.
For PtCl6^2-, let x be the oxidation number of Pt, and -1 be the oxidation number of Cl. Since there are 6 Cl atoms each with an oxidation number of -1, the sum of the oxidation numbers must equal the charge of the ion, which is -2. Therefore, x + 6(-1) = -2. Solving for x, we get x = +4. So, the oxidation number of Pt in PtCl6^2- is +4.
The oxidation number of Pt (platinum) can vary depending on the compound it is in. In its elemental state, platinum has an oxidation number of 0. In some compounds, such as PtCl4, platinum has an oxidation number of +4.
The oxidation number of Pt in PtCl6 is +4. Each Cl has an oxidation number of -1, and since the overall charge of the complex ion is 0, the oxidation number of Pt must be +4 to balance the charges.
The oxidation number for Pt in PtO is +2. Oxygen typically has an oxidation number of -2, so the sum of the oxidation numbers in PtO must be zero since it is a neutral compound.
The oxidation number of Pt in PtCl4^2- is +2. This is because the overall charge of the complex ion is 2-, and each chlorine atom has an oxidation state of -1, so the oxidation state of Pt must be +2 to balance the charge.
For PtCl6^2-, let x be the oxidation number of Pt, and -1 be the oxidation number of Cl. Since there are 6 Cl atoms each with an oxidation number of -1, the sum of the oxidation numbers must equal the charge of the ion, which is -2. Therefore, x + 6(-1) = -2. Solving for x, we get x = +4. So, the oxidation number of Pt in PtCl6^2- is +4.
The oxidation number of Cl in PtCl4^2- is -1. This can be determined by considering that the overall charge of the complex ion is 2-, and each Cl atom has an oxidation number of -1.
The most common oxidation states for Platinum is +2 and +4.
The oxidation state of Pt in PtCl62- is +4. This is because each Cl atom has an oxidation state of -1, and the overall charge of the complex ion is -2. Thus, the oxidation state of Pt can be calculated as follows: x + 6(-1) = -2, where x is the oxidation state of Pt. Solving for x gives x = +4.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2