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For PtCl6^2-, let x be the oxidation number of Pt, and -1 be the oxidation number of Cl. Since there are 6 Cl atoms each with an oxidation number of -1, the sum of the oxidation numbers must equal the charge of the ion, which is -2. Therefore, x + 6(-1) = -2. Solving for x, we get x = +4. So, the oxidation number of Pt in PtCl6^2- is +4.

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