0
+8.
H2 has an oxidation of +1 (A total of +2)
O5 has an oxidation of -2 (A total of -10).
We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.
Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.
Since 10 - 2 = 8, Oxidation number of S is 8.
(no, it did not)
Sorry,
Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.
In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)
2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.
So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]
Hope you got it. (yes, it did so)
What else can I help you with?
In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?
In the compound H2S, hydrogen has an oxidation number of +1, and sulfur has an oxidation number of -2.
What is the oxidation number in H 2?
Zero The oxidation number of an element in any of its elemental forms (allotropes) is always zero
The oxidation number of sulfur in H2 SO4 is?
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
What is the oxidation number of formaldehyde?
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
What is the oxidation number of H2 S O4?
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?
In the compound H2S, hydrogen has an oxidation number of +1, and sulfur has an oxidation number of -2.
In the reaction 2Al plus 3H2SO4 Al2SO43 plus 3H2 in the products has an oxidation number of 0?
Each of the hydrogen atoms in H2 has an oxidation number of 0.
What is the oxidation number in H 2?
Zero The oxidation number of an element in any of its elemental forms (allotropes) is always zero
What is the oxidaton number for hydrogen gas?
H2 has the oxidation number 'zero'
What is the oxidation number of hydrogen usually?
Hydrogen gas (H2) Oxidation number is 0. Hydrogen (H+) is +1.
The oxidation number of sulfur in H2 SO4 is?
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
What is the oxidation number of formaldehyde?
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
In the reaction mg(s) plus 2h2o(i) mg(oh)2(s) plus h2(g) what is the oxidation state of each h in h2(g)?
The answer is 0
What is the oxidation number of H2 S O4?
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
How do calculating oxidation state?
•Total Charge = S charges •H2MnO43- • • •Al(OH)2+ • • • •H2
In CaSO4 the oxidation number of Ca is that of S is and that ofO is?
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
