Zero The oxidation number of an element in any of its elemental forms (allotropes) is always zero
The oxidation number of hydrogen (H) in H2SO4 is +1.
The central carbon atom has an oxidation number of -2 (O is -2, H is +1)
+1 for H +6 for S -2 for each O
The oxidation number of each hydrogen (H) in H3O+ is +1. The oxidation number of oxygen (O) is -2. Overall, the oxidation number of the H3O+ ion is +1.
In N2H4, the oxidation number of nitrogen (N) is -2. Each hydrogen (H) has an oxidation number of +1.
The oxidation number of hydrogen (H) in H2SO4 is +1.
The central carbon atom has an oxidation number of -2 (O is -2, H is +1)
+1 for H +6 for S -2 for each O
The oxidation number of each hydrogen (H) in H3O+ is +1. The oxidation number of oxygen (O) is -2. Overall, the oxidation number of the H3O+ ion is +1.
In N2H4, the oxidation number of nitrogen (N) is -2. Each hydrogen (H) has an oxidation number of +1.
The oxidation number of H in HNO2 is +1, the oxidation number of N is +3, and the oxidation number of O is -2.
The oxidation number for H is almost always 1+.
The oxidation number of H in NaHSO4 is +1. In this compound, Na has an oxidation state of +1, S has an oxidation state of +6, and O has an oxidation state of -2. By adding up the oxidation states and solving for H, it is determined to be +1.
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of oxygen in oxyanions such as this is usually considered to be -2.
Water, or H2O is a free-standing neutral compound, so it's oxidation number is 0. Its atoms have oxidation number though. Hydrogen's oxidation number in water is +1, and oxygen's is -2.