Barium Manganate O.S. of Ba = +2
O.S. of Mn = +6
O.S. of O = -2
The oxidation number of each carbon atom in C6H8O6 is +4. Each hydrogen atom has an oxidation number of +1, and each oxygen atom has an oxidation number of -2.
In S2Cl2, each sulfur atom has an oxidation number of 0, and each chlorine atom has an oxidation number of -1.
The oxidation number for boron in B2H6 is +3, and the oxidation number for hydrogen is -1. Each boron atom has an oxidation number of +3, and each hydrogen atom has an oxidation number of -1 in the B2H6 molecule.
Each Br atom has an oxidation number of zero.
The oxidation number of sulfur in H2S2O8 is +6. Each oxygen atom has an oxidation number of -2, and each hydrogen atom has an oxidation number of +1. By setting up an equation and solving for sulfur's oxidation number, you will find it to be +6.
The oxidation number of each carbon atom in C6H8O6 is +4. Each hydrogen atom has an oxidation number of +1, and each oxygen atom has an oxidation number of -2.
In S2Cl2, each sulfur atom has an oxidation number of 0, and each chlorine atom has an oxidation number of -1.
The oxidation number for boron in B2H6 is +3, and the oxidation number for hydrogen is -1. Each boron atom has an oxidation number of +3, and each hydrogen atom has an oxidation number of -1 in the B2H6 molecule.
Each Br atom has an oxidation number of zero.
The oxidation number of sulfur in H2S2O8 is +6. Each oxygen atom has an oxidation number of -2, and each hydrogen atom has an oxidation number of +1. By setting up an equation and solving for sulfur's oxidation number, you will find it to be +6.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number for HCOO- is -1. This is because in the HCOO- ion, the total charge is -1 and each hydrogen atom has an oxidation number of +1, while the carbon atom has an oxidation number of +2 and the oxygen atoms each have an oxidation number of -2.
The oxidation number of bipyridine is 0 because each nitrogen atom has an oxidation number of -3 in this aromatic compound, and each carbon atom has an oxidation number of -2. The sum of the oxidation numbers in bipyridine adds up to 0.
The oxidation number of ethylenediamine (en) is 0 because each nitrogen atom has a -3 oxidation state and each carbon atom has a +3 oxidation state, resulting in a neutral charge overall.
The oxidation number of aluminum (Al) in Al2S3 is +3, while the oxidation number of sulfur (S) is -2. Each aluminum atom has an oxidation number of +3, and each sulfur atom has an oxidation number of -2 in order to balance the charge in the compound.
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
the oxidation state of each atom