C=4
n= -3
oxygen is -2
OCN has net charge of -1 so here is my expalnation
we will take C as unknown
-2+x-3=-1
x=4
now N is the unknown :
-2+4+x=-1
x=-3
and Oxygen is always -2 except peroxides and others cases...
hope i helped !
In both HCN and HNC molecules, the oxidation number of carbon (C) is -3. This is because hydrogen (H) is almost always assigned an oxidation number of +1, and nitrogen (N) is usually assigned an oxidation number of -3. By assigning the oxidation numbers of H and N, we can then determine the oxidation number of C that makes the overall charge of the molecule neutral.
HCN ( hydrogen cyanide) has the structurte H-C///N ( /// = triple bond). The oxidation number of an atom is the number of outer most electrons used in forming a bond. Not all the outer most electrons are used, some can remain as 'lone pairs'. Carbon ALWAYS has an oxidation no. of '+4' . It never varies. Hydrogen has an oxidaton number of '+1'. It is the nitrogen that has the variable oxidation. number. HCN forms the ions , H^(+) & CN^(-) Since carbon is always '4' and the overall charge of the ion is '-1' , then we can form a sum . 4 + N = -1 N = -1 -4 N = -5 is the oxid'n no/ of nitrogen in HCN. ( All five of nitrgens outer most electrons are involved in the bonding process. ). Compare with ammonia NH3 , Here nitrogen's oxid'n No. is '3' leaving a 'lone pair' of electrons not used in the outer most electron shell.
The minimum oxidation number for nitrogen is -3.
The oxidation number of nitrogen in ammonium nitrite (NH4NO2) is +3. In the ammonium ion (NH4+), nitrogen has an oxidation number of -3 and in the nitrite ion (NO2-), nitrogen has an oxidation number of +3.
The oxidation number of nitrogen in N2 is 0 since it is in its elemental form where the oxidation number is always 0.
In both HCN and HNC molecules, the oxidation number of carbon (C) is -3. This is because hydrogen (H) is almost always assigned an oxidation number of +1, and nitrogen (N) is usually assigned an oxidation number of -3. By assigning the oxidation numbers of H and N, we can then determine the oxidation number of C that makes the overall charge of the molecule neutral.
HCN ( hydrogen cyanide) has the structurte H-C///N ( /// = triple bond). The oxidation number of an atom is the number of outer most electrons used in forming a bond. Not all the outer most electrons are used, some can remain as 'lone pairs'. Carbon ALWAYS has an oxidation no. of '+4' . It never varies. Hydrogen has an oxidaton number of '+1'. It is the nitrogen that has the variable oxidation. number. HCN forms the ions , H^(+) & CN^(-) Since carbon is always '4' and the overall charge of the ion is '-1' , then we can form a sum . 4 + N = -1 N = -1 -4 N = -5 is the oxid'n no/ of nitrogen in HCN. ( All five of nitrgens outer most electrons are involved in the bonding process. ). Compare with ammonia NH3 , Here nitrogen's oxid'n No. is '3' leaving a 'lone pair' of electrons not used in the outer most electron shell.
The minimum oxidation number for nitrogen is -3.
The oxidation number of nitrogen in ammonium nitrite (NH4NO2) is +3. In the ammonium ion (NH4+), nitrogen has an oxidation number of -3 and in the nitrite ion (NO2-), nitrogen has an oxidation number of +3.
The oxidation number of nitrogen in N2 is 0 since it is in its elemental form where the oxidation number is always 0.
The oxidation number of hydrogen in NH3 is +1, and the oxidation number of nitrogen is -3. This is because hydrogen typically has an oxidation number of +1 and in compounds, nitrogen usually has an oxidation number of -3.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
The oxidation number of NO, nitrogen oxide, is +3.
The oxidation number of nitrogen in NO2 is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of NO2 is 0, the nitrogen atom must have an oxidation number of +4 to balance the charges.
The oxidation number of nitrogen in NO is +2. This is because oxygen has an oxidation number of -2, and since the overall charge of NO (nitrogen monoxide) is 0, the nitrogen atom must have an oxidation number of +2 to balance the equation.
The oxidation number of nitrogen in hydrazine (N2H4) is -2. This is because hydrogen usually has an oxidation number of +1, and in this case, since there are two hydrogens bonded to each nitrogen, the total oxidation number for nitrogen must be -2 to balance it out.
The oxidation number of nitrogen can vary depending on the compound it is in. In most cases, nitrogen has an oxidation number of -3 when it is in its elemental form or in compounds like ammonia (NH3). However, in compounds like nitrate (NO3-), nitrogen has an oxidation number of +5.