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I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13

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Calculate the pH of a 0.028 m NACN solution Ka 4.9 x 10 -10. the answer is 10.88 please help?

This is a weak base problem. Assume F = 0.028M Ka = 4.9 10^-10 Kb = Kw / Ka Kw - 10^-14 therefor pKw=14 x = [OH-] Kw / Ka = Kb = x^2 / (F-x) solve for "x" by use of quadratic formula to get the [OH-] pOH = -log [OH-] then plug pOH into the pH equation pH =pKw - pOH


Which of the following describes how the pH of the solution could change?

There factors include: -Ionic strength The number of ions and charges present affect the ion activity coefficient and hence the activity of charges species in the solution -Dilution of buffer with water The pH will change and this will affect the ion activity coefficient. The activity of charges species in the solution is hence affected since water itself can act as an acid or base. -Temperature The effect of temperature on weak acids and its conjugate base as a buffer is small due to small changes in its ionization constant Ka as a function of the temperature. As for a weak base and its conjugate acid, the pH is constant only if the temperature is constant. If the temperature fluctuates, the pH changes according to the changes in pKw for water and pKw is very susceptible to temperature changes.


How do you use pka to find the pH value?

PKa = -log Ka so if you multiply across by -1 and then taking the antilog you can get Ka Ka.Kb = Kw where Kw = 1.0 x 10^14 PKa + PKb = PKw = 14 that should give you a start.


Describe a solution with a pH of 9?

This solution is basic, since it has very little dissolved Hydronium ion. (It has exactly 10-9 hydronium ions per Liter, which is very few. Less hydronium ions means less acidity.) Remember too that a solution with pH > 7 is basic, and a pH < 7 is acidic. Remember that pH is a number that represents the concentration of hydronium ion (H+) in a solution. The equation for this is pH = -log10[H+]. If you have a pH of 9, then you can solve for the concentration of hydronium ions as follows. pH = 9 -9 = log10[H+] You can then raise both sides of the equation to the power of 10 in order to eliminate the log. 10-9=10log10[H+] 10-9=[H+] since 10log10[H+] = [H+] So a pH of 9 indicates a hydronium ion concentration of [H+] = 10-9


What is the most acidic pH 10 pH 3 pH 2 pH 6 pH 8 pH 12 pH 1 pH 75?

pH 1 is the most acidic, as it is closest to 0 on the pH scale. Lower pH values indicate higher acidity.

Related Questions

What is the value of pKw?

pKa+pKb=pKw=14


How many more hydroxide ions are there in a solution with a pH of 9 than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.


How many times more hydroxide ions are there in a solution with a pH than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.


How many times more hydroxide ions are in a solution with a pH of 9 than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.


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Calculate the pH of a 0.028 m NACN solution Ka 4.9 x 10 -10. the answer is 10.88 please help?

This is a weak base problem. Assume F = 0.028M Ka = 4.9 10^-10 Kb = Kw / Ka Kw - 10^-14 therefor pKw=14 x = [OH-] Kw / Ka = Kb = x^2 / (F-x) solve for "x" by use of quadratic formula to get the [OH-] pOH = -log [OH-] then plug pOH into the pH equation pH =pKw - pOH


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1477


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Tlacateotl died in 1426.


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