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What is the pH of a solution that is 0.13 M in NH3 and 0.17 M in NH4Cl?
This represent a buffer of a weak base (NH3) and the conjugate acid (NH4+), so one can use a form of the Henderson Hasselbalch equation like pOH = pKb + log [conj.acid][base]. The pKb for NH3 is 9.25, so pH = 9.25 + log [0.17]/[0.13] = 9.25 + 0.12 = 9.37 = pH
What is the pH of a solution with 0001 M H3O?
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
Which one of the following will form an acidic solution in water a nh4cl b kno3 c lii d naf e none of the above?
A) NH4Cl will form an acidic solution in water because the ammonium ion (NH4+) is a weak acid that will dissociate in water to produce H+ ions, lowering the pH of the solution. The other compounds listed will either not affect the pH significantly or form basic solutions.
What is the ionic compound formula for ammonium chloride?
The ionic compound formula for ammonium chloride is NH4Cl.
Is NH4Cl solution in water is acidic?
Yes, it is slightly acidic due to hydrolysis.
What is the pH of a solution that is 0.13 M in NH3 and 0.17 M in NH4Cl?
This represent a buffer of a weak base (NH3) and the conjugate acid (NH4+), so one can use a form of the Henderson Hasselbalch equation like pOH = pKb + log [conj.acid][base]. The pKb for NH3 is 9.25, so pH = 9.25 + log [0.17]/[0.13] = 9.25 + 0.12 = 9.37 = pH
What will be the pH OF aqueous solution of NH4Cl?
5
What is the pH of a solution with 0001 M H3O?
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
Calculate the pH of 100 ml of a buffer that is 0.060 m NH4Cl and 0.115 m NH3 before and after the addition of 1 ml of 5.30 m HNO3?
pH = pKa - log([HA]/[A])[HA] = concentration weak acid NH4+ and [A] = concentration of weak base NH3 Before HNO3 addition [HA]= 6.0 mmol NH4+ in 100 ml => after: [HA]= 6.0+5.3 mmol NH4+ in 101 mlBefore HNO3 addition [A]= 11.5 mmol NH3 in 100 ml => after: [HA]= 11.5-5.3 mmol NH3 in 101 mlThus: (notice that pH of buffer is independent from a large range of dilution)pHbefore = 9.24- log10(6.0/100 / 11.5/100) = 9.24 - log10(6/11.5) = 9.52and:pHafter = 9.24 - log10(11.3/101 / 6.2/101) = 9.24 - log10(11.3/6.2) = 8.98
Which one of the following will form an acidic solution in water a nh4cl b kno3 c lii d naf e none of the above?
A) NH4Cl will form an acidic solution in water because the ammonium ion (NH4+) is a weak acid that will dissociate in water to produce H+ ions, lowering the pH of the solution. The other compounds listed will either not affect the pH significantly or form basic solutions.
What is the ionic compound formula for ammonium chloride?
The ionic compound formula for ammonium chloride is NH4Cl.
Is NH4Cl solution in water is acidic?
Yes, it is slightly acidic due to hydrolysis.
Why is NH3-NH4CL buffer preferred in edta titration for determination of mg?
The NH3-NH4Cl buffer is preferred in EDTA titration for the determination of magnesium because it helps maintain a relatively constant pH (around 10), which is necessary for the formation of stable complexes between EDTA and magnesium ions. The NH4Cl helps prevent the precipitation of magnesium hydroxide, which could interfere with the titration.
How many centimeter squared are in a meter squared?
there are 1 cm^2 = .0001 M^2
What color does litmus paper turn NH4Cl?
Ammonia turns red litmus paper blue, but does not have any effect on blue litmus parer, since it is a base.
How many grams to the nearest 0.01 g of NH4Cl must be added to 850 mL of 1.103-M solution of NH3 in order to prepare a pH 9.60 buffer?
pOH 14 - pH 4.4 pKb 4.7 4.4 4.7 + log [NH4+]/ 1 x 10^-3 10^- 0.3 0.501 [NH4+]/ 1 x 10^-3 [NH4+] 0.000501 M moles 0.000501 x 0.850L 0.000426 mass 53.49 x 0.000426 0.0228 g
What is the compound for NH4Cl?
Ammonium chloride is an inorganic compound also called NH4Cl.
