This represent a buffer of a weak base (NH3) and the conjugate acid (NH4+), so one can use a form of the Henderson Hasselbalch equation like pOH = pKb + log [conj.acid][base]. The pKb for NH3 is 9.25, so pH = 9.25 + log [0.17]/[0.13] = 9.25 + 0.12 = 9.37 = pH
Usually, ammonia in water solution is presented as NH3.H2O (sometimes NH4OH which is rather incorrect) then NH3.H2O + HCl = NH4Cl + H2O but also this reaction is correct NH3 + HCl = NH4Cl
chloramine NH3 + HCl --> NH4Cl (ammonium chloride, son!)
There are two possible representations of this. NH3(aq) + HCl(aq) --> NH4Cl(aq) or NH4OH + HCl --> NH4Cl + H2O However, this second equations is not entirely accurate as only small amounts of NH4OH will form in an ammonia solution.
NaOH + NH4Cl --> NH3 + H2O + NaCl The products are ammonia, water, and sodium chloride.
The reaction will produce ammonium chloride, NH4Cl.
a balanced equation for the reaction of hydrochloric acid and ammonia solution is given below.HCL(aq) + NH3(l) ---> NH4+(aq) + Cl-(aq) complete .This is the balanced chemical equation .
Usually, ammonia in water solution is presented as NH3.H2O (sometimes NH4OH which is rather incorrect) then NH3.H2O + HCl = NH4Cl + H2O but also this reaction is correct NH3 + HCl = NH4Cl
NH3 + HCl ----> NH4Cl
NH4Cl,sol --> NH3,gas + HCl,gas
chloramine NH3 + HCl --> NH4Cl (ammonium chloride, son!)
There are two possible representations of this. NH3(aq) + HCl(aq) --> NH4Cl(aq) or NH4OH + HCl --> NH4Cl + H2O However, this second equations is not entirely accurate as only small amounts of NH4OH will form in an ammonia solution.
NaOH + NH4Cl --> NH3 + H2O + NaCl The products are ammonia, water, and sodium chloride.
The reaction will produce ammonium chloride, NH4Cl.
Cu(NH3)4SO4
NH3 + HCl -> NH4Cl
nh4oh + nacl however, it further decomposes to create NH3(g)+H2O(l)+NaCl(aq) so the full thing is NaOH (aq) + NH4Cl (s) ---> NaCl (aq) + H2O (l) + NH3 (g) And the ionic equation is OH- (aq) + NH4Cl (s) ---> Cl- (aq) + H2O (l) + NH3 (g)
SrO, LiI, NH4Cl