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This represent a buffer of a weak base (NH3) and the conjugate acid (NH4+), so one can use a form of the Henderson Hasselbalch equation like pOH = pKb + log [conj.acid][base]. The pKb for NH3 is 9.25, so pH = 9.25 + log [0.17]/[0.13] = 9.25 + 0.12 = 9.37 = pH

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Q: What is the pH of a solution that is 0.13 M in NH3 and 0.17 M in NH4Cl?
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