Given:C=0.45M We know that the dissociation constant (Ka) of HCN=6.28 X10-10 Solution: KCN is salt of strong acid and weak base. Kh=Kw/Ka Kh=1 X 10-14/6.2 * 10-10 Kh =1.613 X10-5 ---- Kh=h2C h2=Kh/C =1.613 X 10-5/0.45 =0.3584 X10-4 ---- h=\/0.3584 X 10-4 h =0.6 X 10-2 ---- For a salt of weak acid and strong base, [OH-] = h X C =0.6 * 10-2 X 0.45 [OH-] =2.7 X 10-3 ---- pOH = -log[OH-] =-[log (2.7 X 10-3)] =-[-3 log 10 + log 2.7] =-[-3 + 0.4314] =3 - 0.4314 pOH = 2.5686 ---- pH + pOH = 14 pH = 14 - pOH =14 - 2.5686 pH = 11.4314 ---- Therefore the pH of 0.45M KCN is = 11.4314.
KCN is a salt of strong base weak acid. Therefore its water solution will be basic. Hence, its pH will be greater than 7. ^So what is its pH?
First, calculate the moles of KCN using the formula: moles = Molarity x Volume (in liters). Then, since KCN and HClO react in a 1:1 ratio, the moles of HClO will be equal to the moles of KCN. Finally, calculate the concentration of HClO by dividing the moles of HClO by the volume of the HClO solution in liters.
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
The pH of a 0.1 M solution of HBr (hydrobromic acid) is around 1. It is a strong acid that dissociates completely in water to produce H+ ions, resulting in a low pH.
if 0.000001 is the hydrogen ion concentration the pH is 6
Yes. Since KCN is a salt of strong base and weak acid,its water solution will be basic.Therefore,0.1M KCN have pH greater than 7,its pH is 11.
KCN is a salt of strong base weak acid. Therefore its water solution will be basic. Hence, its pH will be greater than 7. ^So what is its pH?
The answer will depend on the quantity of KCN.
Potassium iodide is neutral. So any solution of potassium iodide would have a pH of 7. One note: no substance has a particular pH as pH depends on both the acidity/basicity of a substance and how concentrated it is.
When potassium cyanide (KCN) is added to water, it dissociates into potassium ions (K+) and cyanide ions (CN-). These ions can then react with water molecules to form stable complexes, such as potassium cyanide ion or hydrocyanic acid, depending on the concentration and pH of the solution. This reaction releases cyanide ions, which can be highly toxic.
First, calculate the moles of KCN using the formula: moles = Molarity x Volume (in liters). Then, since KCN and HClO react in a 1:1 ratio, the moles of HClO will be equal to the moles of KCN. Finally, calculate the concentration of HClO by dividing the moles of HClO by the volume of the HClO solution in liters.
KCN kills a human being in 0.5 second.
To answer this you need a roman numeral on gold to know the charge on it. Assuming it would be (I)... the formula would be KAu(CN)2
We can prepare KCN by the reaction of KOH and HCN.Where HCN can be generated by the pyrolysis of formamide.
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
Examples of poisonous salts: KCN, HgCl2, NaCN.
its PH is 3