- log(0.0235 M HCl)
= 1.6 pH
=============If I remember correctly two places are a pH designation standard.
A 0.00001 M solution of the strong acid HCl will have a pH close to 5, as the concentration is very low, meaning the pH will be closer to neutral. Strong acids like HCl dissociate completely in solution, producing a higher concentration of H+ ions and lower pH.
The pH of a 10^-4 M HCl solution is 4. Since HCl is a strong acid that dissociates completely in water to form H+ ions, the concentration of H+ ions in this solution is equal to the concentration of the HCl solution. pH is calculated as the negative logarithm base 10 of the H+ ion concentration, so pH = -log[H+], which is -log[10^-4] = 4.
The pH of a solution containing 0.1 M of HC2H3O2 is around 2.88.
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
A 0.00001 M solution of the strong acid HCl will have a pH close to 5, as the concentration is very low, meaning the pH will be closer to neutral. Strong acids like HCl dissociate completely in solution, producing a higher concentration of H+ ions and lower pH.
A solution of HCl is highly dissociated into ions, A 0.000001 M solution (1 x 10-6) has a pH of 6 ... close to neutral. A 0.001 M solution (1 x 10-3) has a pH of 3 ... more concenterated, but still not a really concentrated solution. A 0.1 M solution (1 x 10-1) has a pH of 1 ... even more concentrated. showing it is more acidic.
The pH of a 10^-4 M HCl solution is 4. Since HCl is a strong acid that dissociates completely in water to form H+ ions, the concentration of H+ ions in this solution is equal to the concentration of the HCl solution. pH is calculated as the negative logarithm base 10 of the H+ ion concentration, so pH = -log[H+], which is -log[10^-4] = 4.
The pH of a solution containing 0.1 M of HC2H3O2 is around 2.88.
its PH is 3
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
The approximate pH of a 1 M solution of Na2CO3 is around 11-12, making it basic.
For example, to obtain a solution with the pH=7,00 mix: 756 mL 0,1 M solution of Na2HPO4 with 244 mL of 0,1 M HCl solution.
A 1.0 M aqueous solution has a pH of 11.6
The pH of the 0.1 M solution of NaC2H3O2 would be higher than that of the 0.1 M solution of KC2H3O2 as NaC2H3O2 is a strong base and will increase the pH, while KC2H3O2 is a weak acid and will decrease the pH.
The pH value of a solution of ammonium chloride depends on the concentration of the solution. Ammonium chloride is an acidic salt, so a 0.1 M solution would have a pH around 5.6, while a 1 M solution would have a pH around 4.6.