The molar mass of SO3 is 80.06 g/mol. Oxygen makes up three of these four atoms, so the oxygen's molecular weight in SO3 is 48 g/mol (3 x 16). Therefore, the percent by weight of oxygen in SO3 is (48 g/mol / 80.06 g/mol) x 100% = 59.97%.
Sulfur trioxide (SO3) has a molar mass of 80.06 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. Therefore, the percent sulfur by weight in sulfur trioxide can be calculated as: (32.06 g/mol / 80.06 g/mol) x 100 = 40%.
The empirical formula for a compound with 40% sulfur and 60% oxygen by weight would be SO3 (sulfur trioxide). This is because the ratio of sulfur to oxygen is 1:3 in this compound.
To calculate the concentration of sulfur trioxide in oleum, you can use the formula below: Concentration of SO3 = (Oleum concentration x 2) / (3.14) This formula assumes that the oleum concentration is given as a percentage by weight. Simply plug in the value of the oleum concentration into the formula to find the concentration of sulfur trioxide.
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
Oxygen and sulfur both belong to the same group in the periodic table, so they share some similar properties. For example, they can form similar types of chemical bonds and have some similar reactivity patterns. However, they also have distinct differences, such as sulfur typically having a higher atomic weight and forming compounds with a wider range of oxidation states than oxygen.
Sulfur trioxide (SO3) has a molar mass of 80.06 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. Therefore, the percent sulfur by weight in sulfur trioxide can be calculated as: (32.06 g/mol / 80.06 g/mol) x 100 = 40%.
The empirical formula for a compound with 40% sulfur and 60% oxygen by weight would be SO3 (sulfur trioxide). This is because the ratio of sulfur to oxygen is 1:3 in this compound.
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
To calculate the concentration of sulfur trioxide in oleum, you can use the formula below: Concentration of SO3 = (Oleum concentration x 2) / (3.14) This formula assumes that the oleum concentration is given as a percentage by weight. Simply plug in the value of the oleum concentration into the formula to find the concentration of sulfur trioxide.
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
Oxygen
When sulfur is burned, it combines with oxygen from the air to form sulfur dioxide (SO2) gas. This reaction results in an increase in weight as sulfur gains mass from the oxygen atoms it combines with during the reaction. Additionally, any impurities or contaminants present in the sulfur may contribute to the increase in weight after it is burned.
This is a play on words. Sulfur weighs 2 kg when dry because that's its actual weight. When wet, it weighs 1 kg because the water added decreases its weight to 1 kg. When burned, the sulfur combines with oxygen from the air, increasing its weight as part of the chemical reaction with oxygen to form sulfur dioxide.
SO3
Thiourea contains approximately 37.5% sulfur and 11.1% nitrogen by weight.
Oxygen
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.