The percent composition of Silver Chloride is 75.27% silver (Ag) and 24.73% chlorine (Cl).
Beryllium chloride (BeCl2) has a percent composition of approximately 31.0% beryllium and 69.0% chlorine by mass.
To calculate the mass of silver chloride needed to plate 285mg of pure silver, you can start by determining the mass of silver in the silver chloride. Since silver chloride contains 75.27% silver, the mass of silver in the silver chloride is 0.7527 * mass of silver chloride. Once you have the mass of silver in the silver chloride, you can set up a ratio to find the mass of silver chloride needed to plate 285mg of pure silver.
Silver chloride is composed of one silver atom and one chloride atom. The molar mass of silver chloride is 143.32 g/mol and the molar mass of silver is 107.87 g/mol. Therefore, the percentage of silver in silver chloride is (107.87/143.32) x 100 = 75.3%.
Silver chloride can be made by combining silver nitrate with sodium chloride. This will result in a white precipitate of silver chloride forming in the solution. Alternatively, silver chloride can also be made by reacting hydrochloric acid with silver nitrate.
Silver(I) chloride, although it is typically just called silver chloride, because +1 is silver's only valence state.
35%
Beryllium chloride (BeCl2) has a percent composition of approximately 31.0% beryllium and 69.0% chlorine by mass.
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
To calculate the mass of silver chloride needed to plate 285mg of pure silver, you can start by determining the mass of silver in the silver chloride. Since silver chloride contains 75.27% silver, the mass of silver in the silver chloride is 0.7527 * mass of silver chloride. Once you have the mass of silver in the silver chloride, you can set up a ratio to find the mass of silver chloride needed to plate 285mg of pure silver.
If the silver chloride is not dry when its mass is determined, the calculated percent of silver in the alloy will be too low. This is because the presence of water in the silver chloride sample will add extra mass to the compound, leading to an underestimation of the actual silver content in the alloy.
Silver chloride is composed of one silver atom and one chloride atom. The molar mass of silver chloride is 143.32 g/mol and the molar mass of silver is 107.87 g/mol. Therefore, the percentage of silver in silver chloride is (107.87/143.32) x 100 = 75.3%.
To calculate the percent composition by mass of iron in iron (III) chloride (FeCl₃), first determine its molar mass. The molar mass of Fe is approximately 55.85 g/mol, and for Cl, it is about 35.45 g/mol, giving FeCl₃ a total molar mass of approximately 162.2 g/mol (55.85 + 3 × 35.45). The percent composition of iron is then calculated as (mass of Fe / molar mass of FeCl₃) × 100, which is (55.85 / 162.2) × 100 ≈ 34.4%. Thus, the percent composition by mass of iron in iron (III) chloride is approximately 34.4%.
The correct name for AgCl is silver chloride. Its IUPAC name is chlorosilver. Other names for silver chloride are cerargyrite, chlorargyrite, and horn silver.
The percent composition of NaOH can be calculated by dividing the mass of each element by the molar mass of NaOH and then multiplying by 100. For NaOH, the percent composition is approximately 39% Na (sodium) and 61% O (oxygen), as there is only one atom of each in the compound.
Silver chloride can be made by combining silver nitrate with sodium chloride. This will result in a white precipitate of silver chloride forming in the solution. Alternatively, silver chloride can also be made by reacting hydrochloric acid with silver nitrate.
Silver(I) chloride, although it is typically just called silver chloride, because +1 is silver's only valence state.
The atomic mass of silver is 107.868 and the atomic mass of chlorine is 35.453. Therefore, the fraction by mass of silver in silver chloride is 107.868/(107.868 + 35.453) or 0.7526. The precipitated silver chloride therefore contains 0.7526 X 6.21 or 4.674 grams of silver from the coin. The mass percent silver in the coin therefore is 100(4.674/6.80) or 68.7 % silver, to the justified number of significant digits.