0
Silver chloride: AgCl
Atomic Mass of Ag: 107.9 grams
Atomic mass of Cl: 35.5 grams
Molecular mass: 107.9 + 35.5 = 143.4 grams
107.9 grams Ag / 143.4 grams AgCl = .752
35.5 grams Cl / 143.3 grams AgCl = .248
Take the results and multiply by 100 to change to a percent:
.752 × 100 = 75.2% Ag
.248 × 100 = 24.8% Cl
What else can I help you with?
What is the percent composition of Silver Chloride?
The percent composition of Silver Chloride is 75.27% silver (Ag) and 24.73% chlorine (Cl).
Silver chloride often used in silver plating contains 75.27 percent Ag Calculate the mass of silver chloride required to plate 285mg of pure silver?
To calculate the mass of silver chloride needed to plate 285mg of pure silver, you can start by determining the mass of silver in the silver chloride. Since silver chloride contains 75.27% silver, the mass of silver in the silver chloride is 0.7527 * mass of silver chloride. Once you have the mass of silver in the silver chloride, you can set up a ratio to find the mass of silver chloride needed to plate 285mg of pure silver.
What solutions make silver chloride?
Silver chloride can be made by combining silver nitrate with sodium chloride. This will result in a white precipitate of silver chloride forming in the solution. Alternatively, silver chloride can also be made by reacting hydrochloric acid with silver nitrate.
What is the correct name for the compound AgCl?
Silver(I) chloride, although it is typically just called silver chloride, because +1 is silver's only valence state.
What is the precipitate from silver nitrate and ammonium chloride?
The precipitate formed from silver nitrate and ammonium chloride is silver chloride. This reaction occurs because silver chloride is insoluble in water.
What is the percent composition of Silver Chloride?
The percent composition of Silver Chloride is 75.27% silver (Ag) and 24.73% chlorine (Cl).
How do you calculate the percent chloride with the volhard method?
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
Silver chloride often used in silver plating contains 75.27 percent Ag Calculate the mass of silver chloride required to plate 285mg of pure silver?
To calculate the mass of silver chloride needed to plate 285mg of pure silver, you can start by determining the mass of silver in the silver chloride. Since silver chloride contains 75.27% silver, the mass of silver in the silver chloride is 0.7527 * mass of silver chloride. Once you have the mass of silver in the silver chloride, you can set up a ratio to find the mass of silver chloride needed to plate 285mg of pure silver.
If the silver chloride is not dry when its mass is determined will the calculated percent of. silver in the alloy be too high or too low Explain.?
If the silver chloride is not dry when its mass is determined, the calculated percent of silver in the alloy will be too low. This is because the presence of water in the silver chloride sample will add extra mass to the compound, leading to an underestimation of the actual silver content in the alloy.
What is the compound name AgCl?
The correct name for AgCl is silver chloride. Its IUPAC name is chlorosilver. Other names for silver chloride are cerargyrite, chlorargyrite, and horn silver.
What solutions make silver chloride?
Silver chloride can be made by combining silver nitrate with sodium chloride. This will result in a white precipitate of silver chloride forming in the solution. Alternatively, silver chloride can also be made by reacting hydrochloric acid with silver nitrate.
What is the correct name for the compound AgCl?
Silver(I) chloride, although it is typically just called silver chloride, because +1 is silver's only valence state.
What is the precipitate from silver nitrate and ammonium chloride?
The precipitate formed from silver nitrate and ammonium chloride is silver chloride. This reaction occurs because silver chloride is insoluble in water.
What solid is formed upon addition of silver nitrate to a solution of cobalt chloride?
A white solid called silver chloride is formed when silver nitrate is added to a solution of cobalt chloride. This reaction is a double displacement reaction where the silver ions from silver nitrate replace the chloride ions from cobalt chloride to form the insoluble silver chloride precipitate.
A 6.80 g coin is dissolved in nitric acid and 6.21g of AgCl was precipitated by the addition of excess sodium chloride calculate the percent silver in the coin?
The atomic mass of silver is 107.868 and the atomic mass of chlorine is 35.453. Therefore, the fraction by mass of silver in silver chloride is 107.868/(107.868 + 35.453) or 0.7526. The precipitated silver chloride therefore contains 0.7526 X 6.21 or 4.674 grams of silver from the coin. The mass percent silver in the coin therefore is 100(4.674/6.80) or 68.7 % silver, to the justified number of significant digits.
What are some elements that will displace silver in silver I chloride?
Silver chloride is not soluble in water.
Which reaction occurred when potassium chloride and silver acetate react to produce silver chloride and potassium acetate?
When potassium chloride and silver acetate react, a double displacement reaction occurs. The potassium from potassium acetate and silver from silver chloride swap partners to form silver chloride and potassium acetate. Silver chloride is insoluble and precipitates out of the solution.
