When ever a carbonate or bicarbonate reacts with water it evolves CO2 and H2O, in this case HCOOH (Formic acid) is a gas and NaHCO3 is a solid material so aqueous medium (Water) is required for reaction.
NaHCO3 + HCOOH -------> HCOO- + Na+ + H2O + CO2..
CH3COO·C6H4·COOH + NaHCO3 ---> CH3COO·C6H4·COO- + H+ + Na+ + HCO3-
-----> CH3COO·C6H4·COO- + Na+ + H2CO3 og H2CO3 --> H2O + CO2
2 NaHCO3 plus energy --> Na2CO3 plus CO2 plus H2O
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
HCOOH is an acid.
HCHO2 is methanoic acid and is normally written as HCOOH. When reacted with potassium hydroxide (KOH) , it produces potassium methanoate. and water/ HCOOH +KOH = HCOO^-K+ + H2O
methanoic acid = HCOOH sodium hydroxide = NaOH The equation for the reaction is as follows: methanoic acid + sodium hydroxide -> sodium methanoate + water HCOOH + NaOH -> NaCOOH + H2O
Na2CO3 + H2SO4 -> Na2SO4 + CO2 + H2O
2 NaHCO3 plus energy --> Na2CO3 plus CO2 plus H2O
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
No. The correct one is CO + H2O ----> HCOOH (Formic acid)
HCOOH is an acid.
HCHO2 is methanoic acid and is normally written as HCOOH. When reacted with potassium hydroxide (KOH) , it produces potassium methanoate. and water/ HCOOH +KOH = HCOO^-K+ + H2O
methanoic acid = HCOOH sodium hydroxide = NaOH The equation for the reaction is as follows: methanoic acid + sodium hydroxide -> sodium methanoate + water HCOOH + NaOH -> NaCOOH + H2O
NaCO3(aq) + NaHSO4(aq) --> Na2SO4(aq) + CO2(g) + H2O(l)
balls
NaCo3
No.
The molar (not atomic) mass of HCOOH (formic acid) is 46,03 g.