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How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
An acidic solution reacts with magnesium carbonate to produce a gas what is the formula for the gas?
Let's say the acid is HCl MgCO3 + 2 HCl -> Mg Cl2 + H2CO3 H2CO3 is carbonated water (pop) H2CO3 decomposes into H2O and CO2
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
What does nacl hcl kscn reaction gives and what is the color of the product?
The reaction between NaCl, HCl, and KSCN does not directly give any colored products. It typically results in the formation of NaSCN (sodium thiocyanate) and KCl (potassium chloride), with HCl acting as a catalyst. The color of the products is usually white or colorless.
Standardising HCl using Na2CO3 titration. textbook says the solution at the equivalence point is slightly acidic. is it and why?
it depends on the strength of the acid and base used: so, strong acid + strong base = neutral equivalence point strong acid + weak base = acidic equivalence point weak acid + strong base = basic equivalence point In this case, HCl is a strong acid, and Na2CO3 a weak base. Therefore, the equivalence point will be slightly acidic.
What is an exapmple of a chemical change for baking soda?
Baking soda is sodium bicarbonate, NaHCO3. Sodium bicarbonate and hydrochloric acid, HCl, react to form sodium chloride, NaCl and carbonic acid, H2CO3. NaHCO3 + HCl ---> NaCl + H2CO3
How do you balance the equation for Naco3 HCL?
The balanced equation for NaCO3 + HCl is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2. Balancing the equation involves making sure there are the same number of each type of atom on both the reactant and product sides.
What happens when hydrochloric acid is added to sodium bicarbonate?
When HCl reacts with Na2CO3, an acid-base neutralization reaction takes place. 2HCl + Na2CO3 = 2NaCl + H2CO3 H2CO3 further decomposes to give H2O and CO2.
Why HCl react with NaCl?
NaCl and HCl doesn't react.
What is the reaction for Na2CO3 plus HCl?
The reaction between Na2CO3 (sodium carbonate) and HCl (hydrochloric acid) produces NaCl (sodium chloride), H2O (water), and CO2 (carbon dioxide). The balanced chemical equation for this reaction is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2.
Why is there fizzling when you combine sodium carbonate and hydrochloric acid?
The equation for this reaction is: NaCO3 + HCl -----> NaCl + H2O + CO2 CO2 is a gas, so as the reaction proceeds, bubbles of this gas are produced. Thus, the fizzling.
What is the balanced chemical equation for hcl and hco3?
The name is potassium carbonate, but there's NO (balanced) equation for just one compound. An equation is about a reaction e.g. synthesis or decomposition of K2CO3. This should be clearly stated in a question. Please rephrase it.
Combination of HCl and NaOH?
When hydrochloric acid (HCl) and sodium hydroxide (NaOH) are combined in water, they react to form water (H2O) and sodium chloride (NaCl), which is table salt. The reaction is exothermic, meaning it releases heat. The equation for this neutralization reaction is: HCl + NaOH -> NaCl + H2O.
What are the gases evolved from Na2CO3 plus HCL?
Carbon Dioxide. H2CO3 <--> CO2 + H2O
Balanced equation for HCl and NaOH?
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
A balanced symbol equation for sodium hydroxide with hydrochloric acid?
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
