ZnCl2 and H2S, be aware that H2S is extremely poisonus, at low concentrations can kill in a single or few breaths
The balanced chemical equation for the reaction is: ZnS + 2HCl → ZnCl2 + H2S
First, calculate the molar mass of zinc sulfide (ZnS) to be 97.47 g/mol. Then, calculate the number of moles of ZnS in 31.5 g, which is 0.323 mol. From the balanced chemical equation, 1 mole of ZnS reacts with 2 moles of HCl. Therefore, 0.323 mol of ZnS will require 0.646 mol of HCl. Finally, use the formula "Molarity (M) = moles/volume (L)" to find the volume of 5.00 M HCl needed: Volume = 0.646 mol / 5.00 mol/L = 0.129 L or 129 mL.
To determine the volume of 3.00 M HCl needed to react with 25.0 g of zinc sulfide (ZnS), you first need to balance the chemical equation and calculate the moles of ZnS. Utilize the mole ratio to find the moles of HCl needed, then use the molarity of HCl to convert moles to volume (in mL).
The ionic compound ZnS is zinc sulfide.
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
The balanced chemical equation for the reaction is: ZnS + 2HCl → ZnCl2 + H2S
ZnS + 2 HCl --> Zn2+ + 2Cl- + (H2S)gasBe careful!Almost 13 Litre of very toxic (or poisonous and stinky) hydrogen sulfide gas (H2S) will be produced. Only to be performed in absolutely approved and controlled laboratory conditions with a alkaline gas scrubber! Remember: H2S is already poisonous when you can't even smell it.(Its MAC-dose concentration is lower than its odour threshold)Stoiciometric Calculus:56.5 (g ZnS) / 97.474 (g/mol ZnS) = 0.5796 mol ZnS == 0.5796 (mol ZnS) * (2 mol HCl / mol ZnS) = 1.16 mol HClHow many Millilitres you'll need depends on the concentration HCl (in mol/L = mmol/ml ):1.16*103 (mmol HCl) / (concentration HCl) = (1.16*103 / c) ml HCl.This is a single disposition reaction.
First, calculate the molar mass of zinc sulfide (ZnS) to be 97.47 g/mol. Then, calculate the number of moles of ZnS in 31.5 g, which is 0.323 mol. From the balanced chemical equation, 1 mole of ZnS reacts with 2 moles of HCl. Therefore, 0.323 mol of ZnS will require 0.646 mol of HCl. Finally, use the formula "Molarity (M) = moles/volume (L)" to find the volume of 5.00 M HCl needed: Volume = 0.646 mol / 5.00 mol/L = 0.129 L or 129 mL.
The chemical reaction is:ZnCl2 + (NH4)2S = ZnS(s) + 2 NH3 + 2 HCl
To determine the volume of 3.00 M HCl needed to react with 25.0 g of zinc sulfide (ZnS), you first need to balance the chemical equation and calculate the moles of ZnS. Utilize the mole ratio to find the moles of HCl needed, then use the molarity of HCl to convert moles to volume (in mL).
HCl + NaOH -------> NaCl + H2O
ZNS-TV was created in 1977.
ZnS + 2 HCl --> Zn2+ + 2Cl- + (H2S)gasBe careful!Almost 13 Litre of very toxic gaseous (or poisonous and stinky) hydrogen sulfide (H2S, gas) will be produced. Only to be performed in absolutely approved and controlled laboratory conditions with a alkaline gas-scrubber !Remember: H2S is already poisonous when you can't even smell it.(Its MAC-dose concentration is lower than its odour threshold)Stoichiometric calculus:56.5 (g ZnS) / 97.474 (g/mol ZnS) = 0.5796 mol ZnS == 0.5796 (mol ZnS) * (2 mol HCl / mol ZnS) = 1.16 mol HClHow many millilitres you'll need depends on the concentration HCl (in mol/L = mmol/ml ):1.16*103 (mmol HCl) / 7.0 (mmol/ml HCl) = (1.16*103 / 7) = 166 ml HCl
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The ionic compound ZnS is zinc sulfide.
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
The product of reacting ether with NaOH followed by HCl is an alcohol. The initial reaction with NaOH would form an alkoxide ion, which is then protonated by HCl to give the alcohol as the final product.