How many milliliters of hydrochloric acid are needed to react with 56.5g of zinc sulfide?

Answer 1

ZnS + 2 HCl --> Zn2+ + 2Cl- + (H2S)gas

Be careful!Almost 13 Litre of very toxic (or poisonous and stinky) hydrogen sulfide gas (H2S) will be produced. Only to be performed in absolutely approved and controlled laboratory conditions with a alkaline gas scrubber!

Remember: H2S is already poisonous when you can't even smell it.

(Its MAC-dose concentration is lower than its odour threshold)

Stoiciometric Calculus:

56.5 (g ZnS) / 97.474 (g/mol ZnS) = 0.5796 mol ZnS =

= 0.5796 (mol ZnS) * (2 mol HCl / mol ZnS) = 1.16 mol HCl

How many Millilitres you'll need depends on the concentration HCl (in mol/L = mmol/ml ):

1.16*103 (mmol HCl) / (concentration HCl) = (1.16*103 / c) ml HCl.

This is a single disposition reaction.