1. Add Al2O3 at 400 deg C to eliminate the -OH and form 1-methylcyclohexene
2. Add BH3 in THF, then H2O2 in OH- to add an -OH group to the less substituted carbon of the alkene mentioned above (hydroboration-oxidation is anti-Markovnikoff)
3. Add PCC in CH2Cl2 to form your ketone.
I think. Came across this question myself and this is how i solved it. Not 100% sure if its correct though
Under acidic conditions, the reaction of 2-methylcyclohexanol produces 3-methylcyclohexene. The only other place a methyl group could shift is on the first carbon producing 1-methylcyclohexene.
chlorocyclohexane and cyclohexene
I don't know about acidic or alkaline reactions, but in neutral conditions the reaction of iodine with starch is a dark purple color
acidic and basic conditions occur due to what reactions in the body
alkaline conditions
The reaction is:H2O + CO2 = H2CO3
NH4Cl is ammonium chloride. It is the product of an acid-base reaction between ammonia and hydrochloric acid. It is mildly acidic.
I don't know about acidic or alkaline reactions, but in neutral conditions the reaction of iodine with starch is a dark purple color
Salts are neither acidic or alkaline; they are neutral. Salts are a product of a chemical reaction between an acid and a base.
acidic reaction
The nucleophilic oxygen in the alcohol can attack the carbonyl carbon of the aldehyde to form an ester. This reaction can be carried out under acidic conditions.
acidic and basic conditions occur due to what reactions in the body
This is called a neutralization reaction.
Yes
Neutralization
Neutralization
alkaline conditions
The reaction is:H2O + CO2 = H2CO3
auntitatve analysis applied for all reactions such(redox reaction....precepitating reaction...acidic reactions...complexmetry reaction)