The rate law for the reaction A + 2B -> C + D is: rate = k[A][B]^2, where k is the rate constant and [A] and [B] are the concentrations of reactants A and B, respectively.
A + 2 B ==>C + Drate = k[A][B]^2 if this is an elementary step. If not, you cannot determine rate equation.So, #1 would be the best answer, i.e. rate = kAB2 but the square only applies to B and not to A, so it isn't really written correctly.
The rate of the reaction is determined by the rate law, which is typically expressed as Rate = k[A]^m[B]^n, where m and n are the orders of the reactants. If k = 3, A = 2 M, and B = 2 M, and the reaction is kA^2B, then the rate would be 3 x (2)^2 x (2) = 24 M/s.
The reaction of boron with magnesium can be represented by the following equation: 3Mg + 2B -> Mg3B2
If you have a simple generic reaction such asA + 2B ---> 3C + 4DThen the rate is:RATE = -d[A]/dt = -1/2 d[B]/dt = 1/3 d[C]/dt = 1/4 d[D]/dtwhere the "[A]" means the concentration of A.
chemical equation for boron is B and calcium is Ca
A + 2 B ==>C + Drate = k[A][B]^2 if this is an elementary step. If not, you cannot determine rate equation.So, #1 would be the best answer, i.e. rate = kAB2 but the square only applies to B and not to A, so it isn't really written correctly.
8a+2b
12c + 2b
(a + 2b)(a + 2b)
=2b
a + 2b = c a = c - 2b
3Mgo+2B
a-b+a-b+2b+a = 4a
The rate of the reaction is determined by the rate law, which is typically expressed as Rate = k[A]^m[B]^n, where m and n are the orders of the reactants. If k = 3, A = 2 M, and B = 2 M, and the reaction is kA^2B, then the rate would be 3 x (2)^2 x (2) = 24 M/s.
-b+5b-2b=2b
A + 2B cannot be simplified.
They are terms of an algebraic expression that can be simplified to: 2b+2c