MgCl2 contain 25,537 % magnesium and 74,463 % chlorine. The atomic ratio is 2, the mass ratio is approx. 3.
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
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Cl2 has the lowest boiling point of these four substances.
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
The decomposition reaction of magnesium dichloride results in magnesium metal and chlorine gas. The reaction is MgCl2 -> Mg + Cl2.
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
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3 MgCl2 + N2 = Mg3N2 + 3 Cl2
Cl2 has the lowest boiling point of these four substances.
MgCl2 → Mg + Cl2
Bromine is diatomic, so 2 atoms make up Bromine as a reactant. Mg + Br2 ----> MgBr2
They yield magnesium chloride. Mg + Cl2 --> MgCl2
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
Magnesium has a charge of +2 and Chloride has a charge of -1. In order to make magnesium chloride have a net charge of zero, there must be twice as much of the chloride ion than the magnesium ion. The ratio of magnesium to chloride is therefore 1:2. With this knowledge, we can write the chemical equation MgCl2.
The decomposition reaction of magnesium dichloride results in magnesium metal and chlorine gas. The reaction is MgCl2 -> Mg + Cl2.