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What is the formula for a compound formed between aluminum and sulfur atoms?
The formula for the compound formed between aluminum and sulfur atoms is Al2S3. This is because aluminum typically forms a 3+ cation, while sulfur forms a 2- anion, resulting in a compound with a 2:3 ratio of aluminum to sulfur atoms.
How many sulfur atoms are in 1.10 mol of aluminum sulfide?
Aluminum sulfide is Al2S3, which has 3 sulfur atoms per formula unit. 1.10mol means 1.10(6.02x1023), which is 6.62x1023 formula units. Multiple that by 3 to get your sulfur atoms: 6.62x1023(3) = 1.99x1024 sulfur atoms.
What does two atoms of aluminum and three atoms of sulfur make?
Two aluminum atoms and three sulfur atoms would have the formula Al2S3. When writing a formula for an ionic compound, the positive ion (in this case Al3+) is written first. Very often, an ionic compound is composed of a metal and a nonmetal, as in Al2S3, in which case the metal ion will be written first because it will always be positively charged.
Which ionic compound is formed when aluminum and sulfur combine and why?
Aluminum sulfide (Al2S3) is formed when aluminum and sulfur combine due to the transfer of electrons from aluminum to sulfur. Aluminum has a 3+ charge, while sulfur has a 2- charge. This results in the formation of a stable ionic compound with a 2:3 ratio of aluminum to sulfur atoms.
What ionic compound would you expect to form between aluminum and sulfur?
As cations, they retain their original names (examples: aluminum chloride, sulfur dioxide). As anions, they get "ide" endings and become aluminide (very rare) and sulfide (not quite as rare). Combined with oxygen in complex anions, they form aluminates, sulfites, sulfates, etc.
What is the formula for a compound formed between aluminum and sulfur atoms?
The formula for the compound formed between aluminum and sulfur atoms is Al2S3. This is because aluminum typically forms a 3+ cation, while sulfur forms a 2- anion, resulting in a compound with a 2:3 ratio of aluminum to sulfur atoms.
What is the chemical formula for the ionic compound formed from aluminum and sulfur?
The chemical formula for the ionic compound formed from aluminum and sulfur is Al2S3. This compound is formed by the transfer of electrons between aluminum (Al) and sulfur (S) atoms, resulting in the formation of Al3+ and S2- ions which combine in a 2:3 ratio to create Al2S3.
How many sulfur atoms are in 1.10 mol of aluminum sulfide?
Aluminum sulfide is Al2S3, which has 3 sulfur atoms per formula unit. 1.10mol means 1.10(6.02x1023), which is 6.62x1023 formula units. Multiple that by 3 to get your sulfur atoms: 6.62x1023(3) = 1.99x1024 sulfur atoms.
What does two atoms of aluminum and three atoms of sulfur make?
Two aluminum atoms and three sulfur atoms would have the formula Al2S3. When writing a formula for an ionic compound, the positive ion (in this case Al3+) is written first. Very often, an ionic compound is composed of a metal and a nonmetal, as in Al2S3, in which case the metal ion will be written first because it will always be positively charged.
Which ionic compound is formed when aluminum and sulfur combine and why?
Aluminum sulfide (Al2S3) is formed when aluminum and sulfur combine due to the transfer of electrons from aluminum to sulfur. Aluminum has a 3+ charge, while sulfur has a 2- charge. This results in the formation of a stable ionic compound with a 2:3 ratio of aluminum to sulfur atoms.
What is the difference of aluminum sulfide and aluminum sulfate?
Aluminum Sulfide ==> Al2S3 Aluminum Sulfate ==> Al2(SO4)3 Aluminum sulfide is just aluminum and sulfur, while aluminum sulfate is Aluminum plus Sulfate (Polyatomic ion made of sulfur and oxygen)
What ionic compound would you expect to form between aluminum and sulfur?
As cations, they retain their original names (examples: aluminum chloride, sulfur dioxide). As anions, they get "ide" endings and become aluminide (very rare) and sulfide (not quite as rare). Combined with oxygen in complex anions, they form aluminates, sulfites, sulfates, etc.
How many atoms of aluminum will react with 1.33 x 1024 atoms of sulfur to produce aluminum sulfide?
For aluminum sulfide (Al2S3), the ratio of aluminum to sulfur atoms is 2:3. This means that for every 3 atoms of sulfur, 2 atoms of aluminum will react. So, to produce aluminum sulfide from 1.33 x 10^24 atoms of sulfur, you would need (2/3) * 1.33 x 10^24 atoms of aluminum, which is approximately 8.87 x 10^23 atoms of aluminum.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
What is the formula for sulfur tetra bromide?
The formula for sulfur tetrabromide is SBr4. This compound is formed when sulfur reacts with bromine in a 1:4 ratio.
What is empirical formula of aluminum oxide?
The empirical formula of aluminum oxide is Al2O3, which indicates that each aluminum atom is bonded to two oxygen atoms. This ratio of aluminum to oxygen atoms is the simplest whole number ratio in which they combine.
What is the formula form aluminum nitride?
The chemical formula for aluminum nitride is AlN. It is composed of aluminum (Al) and nitrogen (N) atoms in a 1:1 ratio.
