Silver Chloride + Aluminum Nitrate. or AlCl3 + AgNO3 = Al(NO3)3 + AgCl (unbalanced)
3AlCl3 + AgNO3 = Al(NO3)3 + 3AgCl (balanced)
EDIT: I actually believe that the above equation is not balanced correctly.
This is what I got;
AlCl3 + 3AgNO3 = 3AgCl + Al(NO3)3
The Balanced Equation looks like:
6[AgNO3] + Al2(SO4)3 ---> 3[Ag2(SO4)] + 2[Al(NO3)3]
for ions
Silver = Ag+
Nitrate = (NO3)-
Aluminum = (Al)+3
Sulfate = (SO4)-2
3Ag2SO4 + 2AlCl3 ---> 6AgCl + Al2(SO4)3
a precipitate of silver metal and Aluminum nitrate
I think it's a double displacement reaction.
BaNO3 + MnSO4 --> MnNO3 + BaSO4 (Manganes(II) nitrate and barium sulfate) (double replacement reaction)
No reaction will occur between Potassium Sulfate and Ammonium Nitrate.
The reaction forms aluminum sulfate and frees copper.
Lead nitrate + potassium sulfate ---> Lead sulfate + Potassium nitrate
copper sulfate and nitric acid
BaNO3 + MnSO4 --> MnNO3 + BaSO4 (Manganes(II) nitrate and barium sulfate) (double replacement reaction)
No reaction will occur between Potassium Sulfate and Ammonium Nitrate.
The reaction forms aluminum sulfate and frees copper.
Lead nitrate + potassium sulfate ---> Lead sulfate + Potassium nitrate
copper sulfate and nitric acid
The products of the reaction are solid calcium sulfate and aqueous lithium nitrate.
Ammonium sulfate reacts with barium nitrate to form ammonium nitrate and barium sulfate. (NH4)2SO4 + Ba(NO3)2 ==> 2NH4NO3 + BaSO4 It is a double replacement reaction. that is the correct answer
Lead Chromate and Ammonium Sulfate by a double-replacement reaction.
A white precipitate reaction
The spectator ions are Ag+ and (NO3)-.
No Any reaction occurs...
The lead nitrate and sodium sulfate precipitate together and becomes lead sulfate and sodium nitrate. lead nitrate+ sodium sulfate --> lead sulfate + sodium nitrate