When p-nitrophenol reacts with hydrochloric acid, it undergoes protonation of the phenolic hydroxyl group, resulting in the formation of the corresponding p-nitrophenol protonated species. This reaction can be represented as:
p-nitrophenol + HCl ➝ p-nitrophenol-H+ + Cl-.
NaOH is a strong base so it abstracts the proton from p-nitrophenol resulting in the formation of p-nitrophenoxide ion and water, but HCl is a strong acid so its conjugate base (Chloride ion) if in-case abstracts the proton from p-nitrophenol the resulting p-nitrophenoxide will accept the proton released from acid and again changes into p-nitrophenol, so there will not be any effect. Simply p-nitrophenol is also a weak acid & there will not be any reaction of it with strong hydrochloric acid.
In acidic media, p-nitrophenol is colorless. When a base is added, p-nitrophenol changes to a yellow color due to the deprotonation of the phenolic -OH group, forming the anionic form of p-nitrophenol.
The reaction of p-anisidine with hydrochloric acid involves protonation of the nitrogen atom in the aniline ring to form a stable ammonium salt. This results in the formation of a water-soluble salt that can be isolated as a solid precipitate upon addition of a suitable base.
No, p-nitrophenol is not an enzyme. It is a chemical compound that is often used in biochemical research as a substrate for enzyme assays.
I'd do it this way. Use Dow's Process (NaOH) to convert chlorobenzene to phenol. Now, use nitrating mixture to get both o and p- nitrophenol. Fractional distillation should give you what you finally need.
NaOH is a strong base so it abstracts the proton from p-nitrophenol resulting in the formation of p-nitrophenoxide ion and water, but HCl is a strong acid so its conjugate base (Chloride ion) if in-case abstracts the proton from p-nitrophenol the resulting p-nitrophenoxide will accept the proton released from acid and again changes into p-nitrophenol, so there will not be any effect. Simply p-nitrophenol is also a weak acid & there will not be any reaction of it with strong hydrochloric acid.
In acidic media, p-nitrophenol is colorless. When a base is added, p-nitrophenol changes to a yellow color due to the deprotonation of the phenolic -OH group, forming the anionic form of p-nitrophenol.
The reaction of p-anisidine with hydrochloric acid involves protonation of the nitrogen atom in the aniline ring to form a stable ammonium salt. This results in the formation of a water-soluble salt that can be isolated as a solid precipitate upon addition of a suitable base.
http://en.wikipedia.org/wiki/Dinitrophenol
No, p-nitrophenol is not an enzyme. It is a chemical compound that is often used in biochemical research as a substrate for enzyme assays.
I'd do it this way. Use Dow's Process (NaOH) to convert chlorobenzene to phenol. Now, use nitrating mixture to get both o and p- nitrophenol. Fractional distillation should give you what you finally need.
o-nitrophenol forms intramolecular H bond and no association occurs whereas molecules of p-nitrophenol get associated through intermolecular H bonding and boils relatively at higher tem. (above the B.P.of water). Hence,only ortho-nitrophenol is steam volatile.
The mechanism of the PNPP to PNP reaction involves the conversion of p-nitrophenyl phosphate (PNPP) to p-nitrophenol (PNP) by the enzyme alkaline phosphatase. This reaction contributes to the overall process by releasing a phosphate group and producing a colored product that can be measured to quantify the activity of the enzyme.
This is because the two isomers have different boiling points and one of which falls under 100 degrees celsius (2-nitrophenol). hence the first to evaporate out is the 2nitrophenol and the rest will be 4nitrophenol. This is because the two isomers have different boiling points and one of which falls under 100 degrees celsius (2-nitrophenol). hence the first to evaporate out is the 2nitrophenol and the rest will be 4nitrophenol.
Phosphorus pentachloride reacts violently with water and can form explosive mixtures with it. Nonetheless...P-Cl5 + 4H2O ----> H3PO4 + 5H-Clis a hydrolysis reaction (the addition of water to a molecule)
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Ehrlich's reagent, used to detect the presence of indole compounds, typically consists of p-dimethylaminobenzaldehyde dissolved in a strong acid, such as hydrochloric acid or sulfuric acid.