This is not a chemical reaction; it is only a dissolution.
When copper is put into nitric acid, a redox reaction occurs where the copper metal is oxidized to copper(II) ions while the nitric acid is reduced to nitrogen dioxide gas. This reaction produces copper nitrate and water as byproducts.
due to the transfer of electron the zinc nitrate forms to zinc, and copper is formed to copper nitrate. this is usually followed by half equations which are: Cu -> Cu ^2+ + 2e zn^2+ + 2e -> zn where e is electrons and 2+ is representative of the nitrate
Bronze is an alloy that consists of copper and usually tin. When added to nitric acid, the nitrate anions attack the tin and copper cations to produce copper (II) nitrate and Tin (II) nitrate. Nitrogen monoxide is released but reacts with oxygen in the air to produce nitrogen dioxide.
When a piece of copper is placed in a silver nitrate solution, a displacement reaction occurs where the copper solid displaces the silver ions in the solution, forming copper nitrate and solid silver. This reaction is represented by the equation: Cu(s) + 2AgNO3(aq) -> Cu(NO3)2(aq) + 2Ag(s).
When a copper wire is placed in a silver nitrate solution, a redox reaction occurs. Copper atoms from the wire lose electrons to form copper ions in the solution, while silver ions gain electrons to form solid silver. This leads to the deposition of silver metal on the surface of the copper wire.
When copper is put into nitric acid, a redox reaction occurs where the copper metal is oxidized to copper(II) ions while the nitric acid is reduced to nitrogen dioxide gas. This reaction produces copper nitrate and water as byproducts.
no because copper is a less reactive metal
due to the transfer of electron the zinc nitrate forms to zinc, and copper is formed to copper nitrate. this is usually followed by half equations which are: Cu -> Cu ^2+ + 2e zn^2+ + 2e -> zn where e is electrons and 2+ is representative of the nitrate
Bronze is an alloy that consists of copper and usually tin. When added to nitric acid, the nitrate anions attack the tin and copper cations to produce copper (II) nitrate and Tin (II) nitrate. Nitrogen monoxide is released but reacts with oxygen in the air to produce nitrogen dioxide.
When a piece of copper is placed in a silver nitrate solution, a displacement reaction occurs where the copper solid displaces the silver ions in the solution, forming copper nitrate and solid silver. This reaction is represented by the equation: Cu(s) + 2AgNO3(aq) -> Cu(NO3)2(aq) + 2Ag(s).
The blue color in the solution is likely due to the presence of copper ions from the copper wire reacting with the silver nitrate to form a copper nitrate complex. To demonstrate it's a redox reaction, you can show the transfer of electrons from the copper atoms in the wire (losing electrons, getting oxidized) to the silver ions in the solution (gaining electrons, getting reduced).
Nothing. Zinc is more reactive than copper, and zinc has already undergone oxidation to become an ion (remember, zinc nitrate is soluble.) So the copper will just sit there because it's not reactive enough to do anything.
Any reaction occur when gold is put in copper sulfate.
When a copper wire is placed in a silver nitrate solution, a redox reaction occurs. Copper atoms from the wire lose electrons to form copper ions in the solution, while silver ions gain electrons to form solid silver. This leads to the deposition of silver metal on the surface of the copper wire.
Pouring water on it because when it is heated it turns to an endothermic reaction and the hydrated part is boiled put of the compound it is then Anhydrous copper sulphate. When you add water it is hydrated again and this is an exothermic reaction. Which can get extremely hot so don't pour it on your hand and then hydrate it.
The net ionic equation for the reaction between copper and nitric acid is Cu(s) + 2H⁺(aq) + 2NO₃ˉ(aq) → Cu²⁺(aq) + 2NO₃ˉ(aq) + H₂(g). In this reaction, copper is oxidized to form copper(II) ions, and nitric acid is reduced to form water and nitrogen dioxide gas.
When iron(II) nitrate, Fe(NO3)2, is dissolved in water, it ionizes to form Fe2+ ions and NO3− ions. The iron(II) ions will be present in solution as aqua complexes due to their coordination with water molecules. The solution will be pale green in color.