The reduced mass of a molecule is the effective mass of two particles moving in a system, calculated as the reciprocal of the sum of the reciprocal masses. For chloroform (CHCl3), the reduced mass would be calculated based on the masses of the hydrogen (H), carbon (C), and chlorine (Cl) atoms in the molecule.
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
To calculate the percent composition by mass of chloroform (CHCl3), find the molar mass of each element (carbon, hydrogen, and chlorine) and the total molar mass of chloroform. Then, divide the molar mass of each element by the total molar mass and multiply by 100 to get the percentage of each element in chloroform.
The mass of 5.0 mL of chloroform can be calculated by multiplying the volume (5.0 mL) by the density of chloroform, which is approximately 1.49 g/mL. Therefore, the mass of 5.0 mL of chloroform is around 7.45 grams.
(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!
The molar mass of chloroform (CHCl3) is 119.38 g/mol. The molar mass of chlorine in CHCl3 is 35.45 g/mol. To calculate the mass percent of chlorine, divide the molar mass of chlorine by the molar mass of chloroform and multiply by 100%. Therefore, the mass percent of chlorine in chloroform is 29.7%.
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
To calculate the percent composition by mass of chloroform (CHCl3), find the molar mass of each element (carbon, hydrogen, and chlorine) and the total molar mass of chloroform. Then, divide the molar mass of each element by the total molar mass and multiply by 100 to get the percentage of each element in chloroform.
The mass of 5.0 mL of chloroform can be calculated by multiplying the volume (5.0 mL) by the density of chloroform, which is approximately 1.49 g/mL. Therefore, the mass of 5.0 mL of chloroform is around 7.45 grams.
The molar mass of chloroform (CHCl3) is 119.38 g/mol. The molar mass of chlorine in CHCl3 is 35.45 g/mol. To calculate the mass percent of chlorine, divide the molar mass of chlorine by the molar mass of chloroform and multiply by 100%. Therefore, the mass percent of chlorine in chloroform is 29.7%.
(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!
To calculate the number of moles of chloroform in 198 g, you need to divide the mass of chloroform by its molar mass. The molar mass of CHCl3 is 119.38 g/mol, so 198 g ÷ 119.38 g/mol = 1.66 mol of chloroform.
CHCl3 is a useful compound. molar mass of it is 119.5gmol-1.
The molecular formula of chloroform is CHCl3. The molar mass of chlorine is about 35.5 g/mol and the molar mass of chloroform is about 119.4 g/mol. Therefore, the percent by mass of chlorine in chloroform is (35.5 g/mol / 119.4 g/mol) x 100 = approximately 29.7%.
Each chloroform molecule (CHCl3) is composed of 12.5% carbon by mass. Carbon has a molar mass of 12.01 g/mol and accounts for one out of the four atoms in each chloroform molecule.
molar mass of CHCl3 is119.5gmol-1. so there are 0.49 moles.
Each chloroform molecule is composed of one carbon atom, one hydrogen atom, and three chlorine atoms. The molar mass of chloroform is 119.38 g/mol. The molar mass of chlorine is 35.45 g/mol. Therefore, the percentage by mass of chlorine in chloroform is (3 * 35.45 / 119.38) * 100 = 89.3%.
Each chloroform molecule (CHCl3) is composed of 25% hydrogen by mass. This is because the molecular weight of hydrogen is 1, with one hydrogen atom in each chloroform molecule, and the molecular weight of chloroform is 119.38.