-2.37
-2.37 V (apex) Chace
The standard reduction potentials for Mg/Mg^2+ and Cu^2+/Cu are -2.37 V and +0.34 V, respectively. To determine the overall cell potential, you subtract the reduction potential of the anode (Mg/Mg^2+) from the reduction potential of the cathode (Cu^2+/Cu) since the anode is where oxidation occurs. Therefore, the overall cell potential would be 0.34 V - (-2.37 V) = 2.71 V.
0.34 - (-2.37) you're welcome.
The cation for MgCl2 is Mg2+.
Zn2+(aq) +2e- => Zn(s) and Mg(s) => Mg2+(aq) + 2e-
-2.37 V (apex) Chace
-2.37 v
-2.37 v
-2.37 v
The standard reduction potentials for Mg/Mg^2+ and Cu^2+/Cu are -2.37 V and +0.34 V, respectively. To determine the overall cell potential, you subtract the reduction potential of the anode (Mg/Mg^2+) from the reduction potential of the cathode (Cu^2+/Cu) since the anode is where oxidation occurs. Therefore, the overall cell potential would be 0.34 V - (-2.37 V) = 2.71 V.
0.34 - (-2.37) you're welcome.
Mgnesium lost two electrons (reduction).
Mg(s) Mg2+ + 2e-
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
No. This is a redox question. It is asking whether the reaction will occur spontaneously. In order for Mg+2 to spontaneously oxidize Cu(s), Mg+2 needs to have a higher reduction potential (the tendency to be reduced) than Cu+2. Check a redox table to see: Mg2+ + 2 e− --> Mg(s) E° = −2.372 Cu2+ + 2 e− --> Cu(s) E° = +0.340 (More favorable reaction) Cu2+ has a higher reduction potential, meaning Mg2+ will not oxidize Cu(s).
It is the zinc that gets reduced, and the magnesium that gets oxidised. This is because zinc has the higher reduction potential of -0,76 V, compared to magnesiums -2,37 V. The oxidation half cell therefore becomes Mg (s) --> Mg2++ 2e-
The cation for MgCl2 is Mg2+.