The symbol equation for the reaction between iodine and hydrogen is: I2 + H2 -> 2HI.
hydrogen iode because of its 2hydrogen atoms
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
the anwer is , 2NaHCO3 --> Na2CO3 + CO2 + H20:)
The balanced symbol equation for hydrogen peroxide (H2O2) reacting with manganese dioxide (MnO2) is: 2H2O2 + MnO2 -> 2H2O + O2 + Mn
oxygen and hydrogen makes electricity and water
hydrogen iode because of its 2hydrogen atoms
Balanced:H2 + I2 ----> 2 HI
HI
Iodine
The balanced equation for the reaction between hydrogen gas (H2) and iodine gas (I2) to form hydrogen iodide gas (HI) is: H2 + I2 → 2HI
The reaction between hydrogen gas and iodine vapor forms hydrogen iodide gas. The balanced chemical equation for this reaction is: H2(g) + I2(g) -> 2HI(g)
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
Iodine has the symbol I and atomic number 53.
The symbol for Iodine is "I" on the Periodic Table.
The chemical symbol (not equation) of hydrogen is H; the diatomic molecule is H2.
the anwer is , 2NaHCO3 --> Na2CO3 + CO2 + H20:)
The balanced symbol equation for hydrogen peroxide (H2O2) reacting with manganese dioxide (MnO2) is: 2H2O2 + MnO2 -> 2H2O + O2 + Mn