Combination of Hydrogen and iodine
Aluminum powder can react with iodine to form aluminum iodide. This reaction is exothermic and can produce purple fumes of iodine vapor.
The balanced chemical equation for the reaction is: 2H2(g) + O2(g) → 2H2O(g). This equation indicates that when 2 moles of hydrogen gas react with 1 mole of oxygen gas, they produce 2 moles of water vapor.
Sublimation is the process where solid iodine directly turns into iodine vapor without passing through the liquid phase. When the solid iodine is heated, it sublimes into vapor which then collects in the flask as the vapor cools down and condenses.
Well, honey, when iodine is heated, it undergoes sublimation, meaning it goes from a solid directly to a gas without melting into a liquid first. So, technically, the equation for this process is just I2 (s) → I2 (g). Short and sweet, just like me.
Sublimation of iodine to iodine vapor is a physical change. It is a phase transition in which a substance goes directly from a solid to a gas without changing its chemical composition.
When sodium metal reacts with iodine vapor, it forms sodium iodide, which is a white solid compound. The chemical equation for the reaction is: 2Na(s) + I2(g) → 2NaI(s).
When hydrogen iodide breaks down, it forms hydrogen gas and iodine vapor. The reaction is reversible, meaning that hydrogen iodide can reform if hydrogen gas and iodine are combined.
Aluminum powder can react with iodine to form aluminum iodide. This reaction is exothermic and can produce purple fumes of iodine vapor.
The product is water vapor.
2 parts hydrogen gas reacts with 1 part oxygen gas in the air to form water vapor. combustion 2H2 + O2 ---------> 2H20
The chemical equation for hydrogen to water vapor is not possible as stated. In order for hydrogen to form water in any physical state, it must combine with oxygen. The following are the word equation and the chemical equation for hydrogen and oxygen combining to form water. Hydrogen gas plus oxygen gas produces water. 2H2 + O2 --> 2H2O
The combustion of hydrogen requires oxygen, which is supplied by the surrounding air. When hydrogen is combusted, it reacts with oxygen in the equation: 2H2 + O2 --> 2H2O with water (H2O) being the product
The chemical equation for the burning of hydrogen is 2H2 (g) + O2 (g) -> 2H2O (g). This equation represents the combustion reaction where hydrogen gas (H2) reacts with oxygen gas (O2) to form water vapor (H2O) as the product.
Hydrogen and oxygen react with each other to create water.
H2(g) + O2(g) --> H2O(l) unbalanced. 2H2(g) + O2(g) ==> 2H2O(l) balanced.
The balanced chemical equation for the reaction is: 2H2(g) + O2(g) → 2H2O(g). This equation indicates that when 2 moles of hydrogen gas react with 1 mole of oxygen gas, they produce 2 moles of water vapor.
The stoichiometric equation is 2H2 + O2 --> 2H2O. From the given amounts, there are .645 moles of H2 and .325 moles of O2. The limiting reactant is H2, so .645 moles of H2O are formed which is equal to 11.6 grams.