Ag+ + NO3- + H+ + Cl- = AgCl + H+ + NO3-
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
* NaI + AgNO3 = AgI(s) + NaNO3* CH3COONa + AgNO3 ----------CH3COOAg + NaNO3These reagents doesn't react.* 2 Na3PO4 + 3 BaCl2 = 6 NaCl + Ba3(PO4)2(s)* Na2SO4 + BaCl2 = 2 NaCl + BaSO4(s)
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
There are three ions in silver nitrate: one silver ion (Ag+), one nitrate ion (NO3-), and another nitrate ion (NO3-), for a total of three ions.
total ionic equation (also known as the complete ionic equation) for the reaction of potassium carbonate with hydrochloric acid
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
* NaI + AgNO3 = AgI(s) + NaNO3* CH3COONa + AgNO3 ----------CH3COOAg + NaNO3These reagents doesn't react.* 2 Na3PO4 + 3 BaCl2 = 6 NaCl + Ba3(PO4)2(s)* Na2SO4 + BaCl2 = 2 NaCl + BaSO4(s)
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
There are three ions in silver nitrate: one silver ion (Ag+), one nitrate ion (NO3-), and another nitrate ion (NO3-), for a total of three ions.
total ionic equation (also known as the complete ionic equation) for the reaction of potassium carbonate with hydrochloric acid
mercury (I) nitrate and hydrochloric acidOverall Equation: Hg2(NO3)2 (aq) + 2 HCl (aq) -> Hg2Cl2 (s) + 2 HNO3 (aq)Total Ionic Equation: Hg21+(aq) + 2 NO31- (aq) + 2 H1+(aq) + 2 Cl1- (aq) -> Hg2Cl2 (s) + 2 H1+ (aq) + 2 NO31-Net Ionic Equation: Hg21+(aq) + 2 Cl1- (aq) -> Hg2Cl2 (s)
The compound is silver nitrate (AgNO3). By calculating the molar mass of the compound, which is 169.91 g/mol, we can determine the molecular formula. The molar mass of silver is 107.87 g/mol, nitrogen is 14.01 g/mol, and oxygen is 16.00 g/mol. The molar mass of silver nitrate matches the given value.
The chemical equation is:3 AgNO3 + FeCl3 = 3 AgCl + Fe(NO3)33 Ag + 3 NO3- + Fe3+ + 3 Cl- = 3 AgCl(s) + 3 NO3- + Fe3+
The total ionic equation for the reaction between strontium nitrate (Sr(NO₃)₂) and copper(II) sulfate (CuSO₄) can be written as follows: [ \text{Sr}^{2+} (aq) + 2 \text{NO}_3^{-} (aq) + \text{Cu}^{2+} (aq) + \text{SO}_4^{2-} (aq) \rightarrow \text{SrSO}_4 (s) + \text{Cu(NO}_3)_2 (aq) ] In this equation, strontium ions and sulfate ions combine to form solid strontium sulfate (SrSO₄), while copper(II) nitrate remains in solution.
The molecular equation for Cu(NO3)2 and Zn is Cu(NO3)2 + Zn -> Zn(NO3)2 + Cu. The total ionic equation is Cu^2+ + 2NO3- + Zn -> Zn^2+ + 2NO3- + Cu. The net ionic equation is Cu^2+ + Zn -> Zn^2+ + Cu.
To find the concentration of nitrate ions in the mixture, we first calculate the moles of nitrate ions from each salt using the formula moles = concentration x volume. For potassium nitrate: 0.120 mol/L x volume = moles of nitrate ions. For iron (II) nitrate: 0.160 mol/L x volume = moles of nitrate ions. Add the moles of nitrate ions from both salts to get the total moles of nitrate ions in the mixture. Finally, divide the total moles of nitrate ions by the total volume of the mixture to get the concentration of nitrate ions in the mixture.
Cadmium nitrate, which has Cd(NO3)2 for a chemical formula, has a total of 9 atoms in it. There is one cadmium (Cd) atom, and the nitrate radical (NO3) has a nitrogen (N) atom and 3 oxygen (O) atoms in it for a total of 4. But it takes 2 nitrate radicals to balance the equation, and that makes for a nine atom total.