What is the total number of Joules of heat absorbed by 65.00 grams of water when the temperature of th water is raised from 25.00 C to 40.00 C
25.104 kJ
4081.35
105.0j
They begin to move faster. The increased temperature increases the energy of the molecule.
Disrupted.
The solution freezes at a lower temperature and boils at a higher temperature.
The atoms have greater kinetic energy and move faster when the temperature is raised, resulting in more frequent contact between the magnesium atoms and acid molecules, which will cause the rate of the reaction to increase.
If the temperature of the liquid is raised, more molecules escape to the vapor until equilibrium is once again established. The vapor pressure of a liquid, therefore, increases with increasing temperature.
In general, the solubility of a salt increases as the temperature is raised, and thus decreases when the temperature is lowered.
raised temperature or raised temperarely
First, the water must be raised to a temperature of 100 degrees - this requires 4.181 joule/(degree x gram). For example, if your "room temperature" is 20 degrees, multiply that by 8. Then you have to actually evaporate it - that costs 2260 joules/gram.
When the temperature is raised, ensymic actibvity and metabolism increases. The opposite occurs when temperature is lowered.
Yes, you can, but it starts getting complicated. You can, for example have a number raised to an exponent that is itself a number raised to an exponent, or you can have a number raised to an exponent and the result raised to another exponent.
273 k
For every meter it's raised, it gains 833 more joules of gravitational potential energy.
The specific heat capacity of water is about 4180 joules per (kg * kelvin), so you need the mass of the water, and the temperature rise in kelvin (or degrees celcius) example: 1 kg water raised 33 to 34 deg. F ( 0.555 deg. celcius) so, 1 * 0.555 = 0.555, then 0.555 * 4180 = 2320 joules
m=225 g Delta T (change in temperature)= 33 C degrees c (specific heat water liquid)= 1 cal/g(C) Q=? Q=mc(delta T) Q=225g(1 cal/g(C degrees))(33 C degrees) Q= 7425 calories
Yes because any number raised to the power of zero is always equal to 1
A number raised to the second power is a number times itself. This can also be stated as a number squared.
They usually expand and when the temperature gets high enough, turns to liquid.