The carbon in CH3CHCH2 has sp3 hybridization. Each carbon atom forms four sigma bonds, leading to the tetrahedral geometry characteristic of sp3 hybridization.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
The carbon atom in CF4 has a hybridization of sp3.
The hybridization of the carbon atoms in an alkyne is sp.
The hybridization state of each carbon atom in nemotin is sp3.
The carbon atom in CH3CN is sp hybridized.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
The carbon atom in CF4 has a hybridization of sp3.
The hybridization of the carbon atoms in an alkyne is sp.
sp hybridization.
The hybridization state of each carbon atom in nemotin is sp3.
Not quite sure what Hybridization means here, yet No; the only requirement for a compound to be Organic is that it contains Carbon.
The carbon atom in CH3CN is sp hybridized.
The carbon atom in HCN is sp hybridized.
Hyberdization of each carbon in formaldehyde
The carbon atoms are sp2 hybridised.
It should be trigonal planar, and each carbon is sp2 hybridized.
The hybridization of CH3 is sp3. Each carbon atom forms four sigma bonds with hydrogen atoms, resulting in a tetrahedral geometry and sp3 hybridization.